Answer:
This number has 3 significant figures.
Explanation:
Breaking down glucose
Maintaining stable internal conditions
Increasing an organism's temperature
the third one i did the test
Maintaining stable internal conditions
Answer:
Ok; first of all, you must correct the Molecular Formula; FeSO4•7H20
So, work out the Molar Mass;,
(4x18)O+ 55.? Iron + 32 Sulphur, PLUS
(7x 18) H2O = 1 molar mass.
Now, take that times 5.24, show your work & check the Mol. Weights, I am going by memory.
Oxygen
Explanation:
Answer:
There will be produced 66g of CO2 if 45g of glucose completely reacted with oxygen
Explanation:
Step 1 : Balance the formula
Oxidation of glucose can be shown in the following equation :
C6H12O6 + 6 O2 → 6 CO2 + 6H2O
This means that for 1 mole glucose that react there will react 6 moles of O2, to form 6 moles of CO2 and 6 moles of H2O
Step 2: Calculating moles
mole glucose = 45g / Molar mass glucose
⇒ Molar mass = 6*12 + 12*1 + 6*16 = 72 + 12 + 96 = 180g/mole
⇒ mole glucose = 45g / 180g/mole
⇒mole glucose = 0.25 mole
Since 1 mole of glucose is used to form 6 moles of CO2
0.25 mole of glucose is used to form 1.5 moles of CO2
Step 3 : Calculating mass of Carbon dioxide
Mass of CO2 = 1.5 moles of CO2 * 44 g/mole
mass of CO2 = 66g
There will be produced 66g of CO2 if 45g of glucose completely reacted with oxygen
If 45g of glucose reacts with oxygen, 66.015 grams of carbon dioxide would be produced. This calculation is based on converting the mass of glucose to moles, using the stoichiometry of the balanced chemical equation, and then calculating the mass of CO2 produced.
When glucose (which has the chemical formula C6H12O6) is consumed, it reacts with oxygen to produce carbon dioxide, water, and energy. The chemical equation for this reaction is C6H12O6 + 6 O2 → 6 CO2 + 6 H2O. Given that 45g of C6H12O6 completely reacts with oxygen, we need to calculate the mass of carbon dioxide produced from this reaction.
To do this, we first need to determine the molar mass of glucose, which is 180.16 g/mol. This means that 1 mole of glucose weighs 180.16 grams. We can then find out how many moles of glucose 45g represents by dividing 45g by 180.16 g/mol, which gives us 0.25 mol of glucose.
According to the chemical equation, 1 mole of glucose produces 6 moles of CO2. Therefore, 0.25 moles of glucose would produce 0.25 × 6 = 1.5 moles of CO2. The molar mass of CO2 is 44.01 g/mol, so the mass of CO2 produced by 0.25 moles of glucose is 1.5 moles × 44.01 g/mol, resulting in 66.015 grams of CO2. So, if 45g of C6H12O6 completely reacted with oxygen, 66.015 grams of CO2 would be produced.
The gravitational potential energy not only depends on the mass of the substance but also on the height it positioned. Hence, two objects with same mass does not have same potential energy if they are not in same height.
Gravitational potential energy of an object is the energy generated by virtue of its position in gravitational field. Gravitational force is exerted by one object by which it attracts other objects into its centre of mass.
The gravitational force is dependant upon the mass of the object as well to the distance between the objects. Similarly the potential energy p is proportional to the mass m, gravity g and the height from the surface h.
Hence p = mgh.
As per this relation potential energy is not only affected by the mass but also the height at which the objects are located.
If an object is placed at a height higher than other object having same mass then it stores greater potential energy. Hence, we can't agree with the statement .
To find more on potential energy refer here:
#SPJ2
Answer:
the above screenshot has the answers
Answer:
(a) Avoid parallax error
(b) To ensure that almost all the SCN⁻ has reacted.
Explanation:
(a) Avoiding bias
A Mohr pipet is a graduated pipet. To avoid bias, you should always hold the pipet so the meniscus is at eye level.
If your eye is above or below the meniscus, you will get an incorrect reading of the volume.
(b) Excess Fe³⁺
I am guessing that you are adding different volumes of SCN⁻ to Fe³⁺ to generate a Beer's Law plot of the concentration of FeSCN²⁺.
The problem is that the reaction is an equilibrium It does not go to completion.
Fe³⁺ + SCN⁻ ⇌ FeSCN²⁺
You use a large excess of Fe³⁺ to drive the position of equilibrium to the right and make sure that almost all the added SCN⁻ is converted to FeSCN²⁺.
change in the temperature of the steel?
Answer:
1279 °C
Explanation:
Data Given:
Amount of Heat absorb = 5.82 x 10³ KJ
Convert KJ to J
1 KJ = 1000 J
5.82 x 10³ KJ = 5.82 x 10³ x 1000 = 5.82 x10⁶ J
mass of sample = 8.92 Kg
Convert Kg to g
1 kg = 1000 g
8.92 Kg = 8.92 x 1000 = 8920 g
Cs of steel = 0.51 J/g °C
change in temperature = ?
Solution:
Formula used
Q = Cs.m.ΔT
rearrange the above equation to calculate the mass of steel sample
ΔT = Q / Cs.m .... . . . . . (1)
Where:
Q = amount of heat
Cs = specific heat of steel = 0.51 J/g °C
m = mass
ΔT = Change in temperature
Put values in above equation 1
ΔT = 5.82 x10⁶ J / 0.51 (J/g °C) x 8920 g
ΔT = 5.82 x10⁶ J /4549.2 (J/°C)
ΔT = 1279 °C
So,
change in temperature = 1279 °C