A runner has a track lap of one minute while at a run, five minutes while at a jog, 7 minutes while at a walk. If 2/5 of the lap is paced at a run, 1/2 at a jog and 1/10 at a walk what is the total track lap time of the runner. Write the solution as a mixed number or a fraction in lowest terms

Answers

Answer 1
Answer: 24 seconds running
2 minutes 30 seconds jogging
42 seconds walking
3 minutes 36 seconds in that lap
Answer 2
Answer:

Final answer:

The total track lap time of the runner is 2 2/5 minutes or 2.4 minutes.

Explanation:

The total track lap time of the runner can be calculated by summing up the individual time spent at each pace (run, jog, walk). Each pace's time is first multiplied by the fraction of the lap completed at that pace.

For the run, the calculation is 2/5 of 1 minute which is 2/5 minute.

For the jog, the calculation is 1/2 of 5 minutes which is 5/2 = 2 1/2 minutes or 2.5 minutes in decimal form.

For the walk, the calculation is 1/10 of 7 minutes which is 7/10 = 0.7 minutes.

Adding these times together gives a total of (2/5) + (5/2) + (7/10) = 12/5 = 2 2/5 minutes or 2.4 minutes in decimal form.

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Simplest form of the expression
3sqrt750+3sqrt2058-3sqrt48.

Answers

3√(750)+3√(2058)-3√(48)\n=3√(30*25)+3√(42*49)-3√(3*16)\n=15√(30)+21√(42)-12√(3)

Need help with this question

Answers

a₁ = -8  This is the first term in an arithmetic sequence.
d = 3, the common difference

a(n) = a₁ + d(n-1)

a₇ = -8 + 3(7-1)
a₇ = -8 + 3(6)
a₇ = -8 + 18
a₇ = 10

To check:
a₁ = -8
a₂ = -8 + 3 = -5
a₃ = -5 + 3 = -2
a₄ = -2 + 3 = 1
a₅ = 1 + 3 = 4
a₆ = 4 + 3 = 7
a₇ = 7 + 3 = 10

The area of a trapezoid is 150 in squared if the height is 8 in. And the longer base is 23 in. What is the length of the shorter base ?

Answers

A=150in^2\n\nh=8in;\ a=23in;\ b=?\n\nA=(a+b)/(2)\cdot h\n\n(23+b)/(2)\cdot8=150\n\n(23+b)\cdot4=150\ \ \ \ /:4\n\n23+b=37.5\ \ \ \ /-23\n\nb=14.5\ (in)\leftarrow answer

Bety compró 16 pares de calcetas, entre blancas y negras, y pagó $339. Los pares de calcetas blancas cuestan $24 y las negras $19. Plantea el sistema de ecuaciones y resuelve por el método que creas conveniente. Después toma foto y súbela en donde se indica.

Answers

Answer:

Sistema de ecuaciones:

x+y= 16

24x+19y=339

Respuesta:

x=7, y=9

Step-by-step explanation:

Con la información del enunciado puedes plantear las siguientes ecuaciones:

x= cantidad de calcetas blancas

y= cantidad de calcetas negras

x+y= 16 (1)

24x+19y=339 (2)

Para resolver las ecuaciones, debes iniciar despejando x en 1:

y=16-x (3)

Después, debes reemplazar (3) en (2) y despejar x para encontrar su valor:

24x+19(16-x)=339

24x+304-19x=339

5x=339-304

x=35/5

x=7

Luego, puedes reemplazar el valor de x en (3) para encontrar y:

y=16-x

y=16-7

y=9

De acuerdo a esto, x= 7, y=9.

Given the values in the probability distribution table, determine the standard deviation. A. 3.2
B. 13.9
C. 3.9
D. 2.0

Answers

Answer:

D. 2.0 is the right answer

Step-by-step explanation:

Note: All decimals were converted to fractions.

The standard deviation of the given distribution is:

σ=1.965

Answer:

1.96

Step-by-step explanation:

Solution:-

- We will use the table given to determine the standard deviation of random variable x. From descriptive statistics we have the following formula for standard deviation (s.d) :

                s.d (x) = sqrt ( Var(x) )

- The formula for Variance ( Var (x) ) is also taken from descriptive statistics as follows:

                Var(X) = E ( X^2) + [ E(X) ] ^2

- Where,

                E ( X^2) = 0^2*0.15 + 1^2*0.07 + 2^2*0.19 + 3^2*0.09 + 4^2*0.16 + 5^2*0.23 +6^2*0.11 \n\nE ( X^2) = 13.91 \n\n

               

                E(X) = 0*0.15\:+\:1*0.07\:+\:2*0.19\:+\:3\cdot \:0.09\:+\:4\cdot \:0.16\:+\:5\cdot \:0.23\:+6\cdot \:0.11\n\nE(X) = 3.17\n\n(E(X))^2 = 10.0489

- So the variance is:

                Var ( X ) = 13.91 - 10.0489 = 3.8611

                s.d (x) = √3.8611 = 1.96

If f(2)=pi+7 then f^-1(pi+7)=?

Answers

Answer: The required value of f^('-1)(\pi+7) is 2.

Step-by-step explanation:  We are given the following value of a function f :

f(2)=\pi+7.

We are to find the value of f^(-1)(\pi+7).

We know that

For any function g(x) = y,

g^(-1)(y)=x.

Applying the above rule in equation (i), we get

f(2)=\pi+7\n\n\Rightarrow f^(-1)(\pi+7)=2.

Thus, the required value of f^('-1)(\pi+7) is 2.

Hello,

f(2)=\pi + 7\n\n 2=f^(-1)\ o\ f(2)=f^(-1) (f(2))=f^(-1)( \pi + 7 })