B.epidermis
C.gastric
D.sedentary
It lends legitimacy to the speaker's claim that she knows what love is..
It adds to the high standard the speaker is claiming one must meet to love another.
Answer:
D
Explanation:
Plato
B. They are making a religious journey to a cathedral.
C. They are escaping religious oppression in England.
D. They are all members of the Knight's entourage.
Answer:
c
Explanation:
The characters in the Prologue from The Canterbury Tales are brought together by a religious journey to a cathedral.
The correct answer is B. They are making a religious journey to a cathedral.
In the Prologue of The Canterbury Tales, the characters are introduced as a group of pilgrims who are traveling together on a religious journey to the Canterbury Cathedral. They are all from different walks of life, representing different social classes and professions. This pilgrimage serves as the initial event that brings the characters together and sets the stage for the tales they will tell during their journey.
For example, the Knight is a member of this group and is one of the characters introduced in the Prologue. However, it is important to note that not all characters in the Prologue are members of the Knight's entourage, so option D is incorrect.
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Answer:
A. After 3.57 seconds, the racecar will overtake the stock car
B. distance travelled = 37. 59 m
C. v₁ = 21.06 m/s
v₂ = 16.45 m/s
Explanation:
Using, S = ut + 1/2at² where s is displacement, u is initial velocity, t is time, a is acceleration.
Car 1 has acceleration a = +5.9 m/s²; Car 2 has acceleration a = +3.6 m/s²
A. The time for the two cars to be directly side by side be t.
Beyond time, t, Car 1 will overtake Car 2.
Since both cars are starting from rest, initial velocity, u, = 0
S = 1/2at²
For car 1, time t = t - 1.0 since it started 1.0 second behind car 2
s₁ = 1/2 * 5.9 * (t - 1)²
s = 2.95t² - 5.9t + 2.95
For car 2; s₂ = 1/2 * 3.6 * t² = 1.8t²
at time t, the displacement of the two cars will be equal; s₁ = s₂
2.95t² - 5.9t + 2.95 = 1.8t²
1.15t² - 5.9t + 2.95 = 0
solving for t using the quadratic formula
t = (5.9 ± 4.61)/2.3
t = 4.57 s or 0.56 s
since t cannot be less than 1.0 s, t = 4.57 s
Time for car 1 = (4.57 - 1.0) s = 3.57 s
Therefore, after 3.57 seconds, the racecar will overtake the stock car
B. The distance travelled by both cars, s = 1/2 * 3.6 * 4.57² = 37.59 m OR
s = 1/2 * 5.9 * 3.57² = 37.59 m
distance travelled = 37. 59 m
C. Using v² = u² + 2as; since u = 0, v² = 2as
velocity of car 1; v₁² = 2 * 5.9 * 37.59
taking square root of both sides
v₁ = 21.06 m/s
velocity of car, v₂² = 2 * 3.6 * 37.59
taking square root of both sides
v₂ = 16.45 m/s