Which shows one way to determine the factors of x3 – 12x2 – 2x + 24 by grouping? plzzzzz answerr x(x2 – 12) + 2(x2 – 12) x(x2 – 12) – 2(x2 – 12) x2(x – 12) + 2(x – 12) x2(x – 12) – 2(x – 12)

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

The idea of factoring by grouping is that you don't move anything around.  You leave the polynomial in descending order of powers of x and group them together in groups of 2.

(x^3-12x^2)-(2x+24)=0

Then you factor out what is common in each set of parenthesis.

x^2(x-12)-2(x-12)

You know if factoring by grouping "works" if what's inside both sets of parenthesis is exactly the same.  Both of ours are (x - 12), so grouping "worked".  Match the factoring above to one of your answers.

Answer 2
Answer:

Answer:

For anyone else viewing this, the answer is option D.

Step-by-step explanation:

This is my evidence. Please mark me brainliest and have a fantastic day!


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Sam y have ages that are consecutive odd integers. The product of their ages is 783. Which equation could be used to find Jeremy's age, j, if he is the younger man?

Answers

sam and jeremy
consecitive odd
means they are 2 years apart
j is younger
j+2=s
product is 783
783=js
s=j+2
783=j(j+2)
783=j^2+2j
minus783 both sides
0=j^2+2j-783
factor or use quadratic formula
0=(j-27)(j+29)
set to zero

0=j-27
add 27
27=j

0=j+29
minus 29
-29=j
false, cannot be negative age

answer is jeremy is 27 years old

Evaluate P(3, 0).
0
1
6

Answers

Answer:

Option B. 1

Step-by-step explanation:

We have to find the value of P(3, 0)

We have to find the value of given permutation ^(3)P_(0)

Since we know ^(a)P_(b)=(a!)/((a-b)!)

Here a = 3

b = 0

^(3)P_(0)=(3!)/((3-0)!)

=(3!)/(3!)=1

Therefore, option B. 1 is the answer.

_(3)P_(0) = (3!)/((3 - 0)!)
_(3)P_(0) = (3!)/(3!)
_(3)P_(0) = (3 * 2 * 1)/(3 * 2 * 1)
_(3)P_(0) = 1

The answer is B.

If 12(5r + 6t) = w, then in terms of w, what is 48(30r + 36t)

Answers

The 12 is multiplied by 4 to get 48, andthe (5r + 6t) is multiplied by 6 to get (30r + 36t), thereforeyou are multiplying the outside by 4 and the inside by 6, puttingthose together is 24 for a factor.If 12(5r + 6t) = w, then48(30r + 36t) is equal to 24w.

Draw a set of objects where you can find a fractional part of the group using the total number of objects by using subgroups

Answers

Answer:

Draw 20 equilateral triangles such that 5 triangles having sides measure 4 cm , 7 triangles have sides measure 7 cm , 3 triangles have side 10 cm and rest of the triangles have side of measure 5 cm.

This will become a set of equilateral triangles .

Let consider a subgroup set of the original set of having equilateral triangle with side-length of 5 cm.

Then the number of triangle having side-length 5 cm= 20-5-7-3=5

Now, the fraction of the group having triangle with side- length 5 cm is given  by:-

\frac{\text{triangle having side-length 5 cm}}{\text{total triangle}}=(5)/(20)=(1)/(4)

We divide the total set into several sub-sets (subgroups) that contain the exact same number of members. This way we know the number of total members by adding the number of total subsets.

What is the greatest common factor of 42a^5b^3, and 42ab^4

Answers

the greatest common factor of 36x3 and 8x is simply 4X

Bruce has a bottle that contains 60% of lemon juice and the rest water. The bottle has 1 liter of water.Part A: Write an equation in one variable that can be used to find the total number of liters of lemon juice and water in the bottle. Define the variable used in the equation. (5 points)

Answers

Given:
lemon juice = 60% in the bottle
water = 1 liter.

Since lemon juice is 60% and the rest is water. Water is 40% of the bottle.

1 liter of water is equivalent to 40% of the bottle.

1/40% = 2.50 liters amount of total liquid in the water.

2.50 x 60% = 1.5 liters of lemon juice.

0.6x + 0.4x = 2.5