You are given a bag with 10 balls, of which 3 are red, 3 are blue, 1 is yellow, 2 are black, and 1 is white. You pick one ball, note its color, put the ball back in the bag, and then pick another ball. The probability that it was the case that the first ball was black and the second ball was red is

Answers

Answer 1
Answer:

Answer:

3/50

Step-by-step explanation:

P( 1st ball is a black ball) = number of black balls/ total balls

                    = 2/10 = 1/5

We put the ball back so we still have the same number of balls

P( 2nd ball is a red ball) = number of red balls/ total balls

                    = 3/10

P (1st ball black, 2nd red) = P( 1st ball is a black ball)* P( 2nd ball is a red ball)

                                          =1/5* 3/10

                                          = 3/50


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The square root of 1.69 is ____

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Answers

Answer:

1.3

Step-by-step explanation:

The square root of 1.69 is 1.3.

Answer:

1.3

Step-by-step explanation:

1.3*1.3=1.69

Hope this helps:) Have a good day!

What is the correct order of operations for simplifying the expression (x+3)^2-(x^2+9)/2x^2

Answers

Answer with explanation:

The correct order of simplifying the expression is:

1. Opening the bracket Using Identity

2. Adding and Subtracting Like terms

The given expression is

=((x+3)^2-(x^2+9))/(2x^2)\n\n=(x^2+6 x+9-x^2-9)/(2x^2)\n\n=(6x)/(2x^2)\n\n=(3)/(x)\n\n \text{Used the identity and law of indices}\n\n(a+b)^2=a^2+2 a b+b^2\n\n (x^a)/(x^b)=x^(a-b)

((x+3)^2-(x^2+9))/(2x^2)\n\nuse\ (a+b)^2=a^2+2ab+b^2\n\n=(x^2+2\cdot x\cdot3+3^2-x^2-9)/(2x^2)=(x^2-x^2+6x+9-9)/(2x^2)\n\n=(6x)/(2x^2)=(3)/(x)

54+(x-4)=x ............

Answers