5x+4y+100 in slope intercept form

Answers

Answer 1

Answer: y = mx + b
5x + 4y + 100 = 0
4y = - 5x - 100
y = - 1,25x - 25

Related Questions

Lucy correctly answered 70% of the questions on her science homework. She counted 14 correct answers. How many questions are there on her homework?
Please 20 points like rn 5 mins left on test
In the library there are 200 books. 58 of them are non-fiction. What percentage of the books are non-fiction?
The radii of Earth and Pluto are 6,371 kilometers and 1,161 kilometers, respectively. Approximately how many spheres the size of Pluto does it take to have the same volume as Earth?
How are the two functions f(x) = 0.7(6)^x and g(x) = 0.7^-x related to each other?

An object is sold for $2 but is on sale for 40% off. What is the final price?

Answers

5 cents or $1.20 I'm not fully sure but it's one of the two

What is the square root of 67

Answers

Every positive number has two square roots.

The square roots of 67 are 8.185... (rounded) and -8.185... (rounded) .

Both are irrational numbers, so they can't be completely written down
with digits. No matter how many decimal places I write, it can never be
enough, because these decimals go on forever and never end.

The square root of 67 is, 8.18535277187

Next term in sequence 61, 122, 244, 488

Answers

next term is 976 because the sequence is 976=2x488=2x2x244=2x2x2x122=2x2x2x2x61

Answer:

u would add 488+488 so it = 976

Step-by-step explanation:

The dataset below represents the population densities per square mile of land area in 15 states in the 2010 U.S. Census. What is the interquartile range?

Answers

Answer:

The Interquartile range is 188

Step-by-step explanation:

Missing Data:

1,19,35,43,49,55,63,94,105,110,175,231,239,351,738

Required

Determine the Interquartile range (IQR)

The given data is ordered already.

First, we need to determine the median

For odd number of data

Median = ½(n + 1)th

In this case, n = 15; so

Median = ½(15 + 1)th

Median = ½(16)th

Median = 8th

This implies that the median is at the 8th position.

So, we have:

1,19,35,43,49,55,63 ----> Lower

(94) ---- Median

105,110,175,231,239,351,738 ---- Upper

Next, we determine the median of the lower and upper sets.

These are called lower quartile (Q1) and upper quartile (Q3) respectively

Lower: 1,19,35,43,49,55,63

Number of data, n = 7

Q1 = ½(n + 1)th

Q1 = ½(7 + 1)th

Q1 = ½(8)th

Q1 = 4th position

From the list of data in the lower set,

Q1 = 43

Upper: 105,110,175,231,239,351,738

Number of data, n = 7

Q3 = ½(n + 1)th

Q3 = ½(7 + 1)th

Q3 = ½(8)th

Q3 = 4th position

From the list of data in the upper set,

Q3 = 231

IQR is then calculated as thus:

IQR = Q3 - Q1

IQR = 231 - 43

IQR = 188

The distribution of heights for adult men in a certain population is approximately normal with mean 70 inches and standard deviation 4 inches. Which of the following represents the middle 80 percent of the heights ? A. 2.5% B. 5% C. 16% D. 1%

Answers

The interval that represent the middle 80% of the heights (inches) is [64.88, 75.12].

Step-by-step explanation:

Given :

Mean -- $\rm \mu = 70 \; inches$

Standard Deviation -- $\rm \sigma = 4 \; inches$

Calculation :

We want to know an interval in which the probability that a height falls there is 0.8.

In such interval, the probability that a value is higher than the right end of the interval is

$\rm P(x>z) = \frac {1-0.8}{2} = 0.1$

If x is the distribuition of heights, then we want y such that P(x > y) = 0.1.

$Z = (x-\mu)/(\sigma)$

Now, let

$U = (y-70)/(4)$

We have

$\rm 0.1 = P(x>y)= P((x-70)/(4) > (y-70)/(4))=P(Z>U)=1-\phi(U)$

$\phi (U) = 1-0.1=0.9$

by looking at the table, we find that U = 1.28, therefore

$(y-70)/(4)=1.28$

$1.28* 4 + 70 = y$

$y=75.12$

The other end of the interval is the symmetrical of 75.12 respect to 70, hence it is

70- (75.12-70) = 64.88.

The interval that represent the middle 80% of the heights (inches) is [64.88, 75.12].

For more information, refer the link given below

brainly.com/question/10729938?referrer=searchResults

Answer:

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12]

Step-by-step explanation:

I beleive those options corresponds to another question, i will ignore them. We want to know an interval in which the probability that a height falls there is 0.8.

In such interval, the probability that a value is higher than the right end of the interval is (1-0.8)/2 = 0.1

If X is the distribuition of heights, then we want z such that P(X > z) = 0.1. We will take W, the standarization of X, wth distribution N(0,1)

$W = (X-\mu)/(\sigma) = (X-70)/(4)$

The values of the cumulative distribution function of W, denoted by $\phi$ , can be found in the attached file. Lets call $y = (z-70)/(4)$ . We have

$0.1 = P(X > z) = P((X-70)/(4) > (z-70)/(4)) = P(W > y) = 1-\phi(y)$

Thus

$\phi(y) = 1-0.1 = 0.9$

by looking at the table, we find that y = 1.28, therefore

$(z-70)/(4) = 1.28\nz = 1.28*4+70 = 75.12$

The other end of the interval is the symmetrical of 75.12 respect to 70, hence it is 70- (75.12-70) = 64.88.

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12] .

If the length of a rectangle isexpressed by 22 + 41-8 and the
width is 3x What is the area of the
rectangle?

Answers

I think that the length's area is 6075

Other Questions

A worker at a mill is loading 5 pound bags of flour into boxes to deliver to a local warehouse. Each box holds 16 bags of flour. If the warehouse orders 4 tons of flour how many boxes are needed to fulfill the order ?

Solve the question: 12y = 132. A. Y = 144 B. Y = 1/11 C. Y = 11/12 D. Y = 11

An insurance agent can earn 10% in commission on auto insurance policies. If an insurance agent quoted you $1,200 annual premium for your car insurance, how much would the agent earn?

Which of the following is a solution of 4x2 = − 9x − 4?