Answer:
Molar mass = 50.4 g/mol
Explanation:
Pressure . Volume = number of moles (n) . R . T°K
This is the Ideal Gases Law where R is the Ideal Gases Constant and T°, Absolute Temperature.
We convert the T°C to T°K → 190°C + 273 = 463 K
R = 0.082 L.atm /mol.K
We need to convert the volume from mL to L → 2160 mL . 1L / 1000 mL = 2.16 L; now we replace:
1 atm . 2.16L = n . 0.082 L.atm /mol.K . 463K
(1 atm . 2.16L) / (0.082 L.atm /mol.K . 463K) = n → 0.569 moles
These moles refers to 2.87 g so let's find out the molar mass:
Molar mass (g/mol) = 2.87 g / 0.0569 mol = 50.4 g/mol
Answer:
False
Explanation:
This property depends on the intermolecular interactions of the analyzed compound.
In most cases, this property is fulfilled, but one of the most important exceptions is water since ice cubes float in liquid water which means that its density is lower than that of liquid water.
This is due to one of the types of bonds that binds hydrogen bonds to water molecules.
Hydrogen bridges are a molecular interaction that occurs between the hydrogen in one molecule of water and the oxygen in another molecule.
Recall the formula of the density
The volume is inversely proportional to the density this means that the lower the volume the higher the density and the higher the volume the lower the density.
This type of bonding means that when the freezes there is more space between the molecules, then they occupy a larger volume
Therefore, if we have the same mass in the liquid state and the solid-state, the molecules in the liquid state will be closer together occupying less volume (higher density) and the molecules that are in the solid-state occupy a greater volume (lower density)
The correct answer is that is repulsive forces between specific lone pairs of electrons.
Further Explanation:
The total number of valence electrons of is calculated as,
Total valence electrons (TVE) = [(1) (Valence electrons of O) + (2) (Valence electrons of H)]
In , the total number of valence electrons is 8. Here, oxygen forms single bond with the hydrogen atom and therefore, 2 pair of electrons are used in the formation of two single bonds with hydrogen atom. Remaining 2 pair of electrons are used to complete the octet of oxygen atom. Therefore, contains two bond pairs and two lone pairs (refer to the image attached).
According to the VSEPR theory, central atom oxygen has two bond pair with two lone pair, therefore, has an arrangement. Therefore, these four pairs of electrons spread out as tetrahedral arrangement to minimize lone pair-lone pair and bond pair-bond pair repulsion. Since lone pairs are not considered in the shape of the molecule and therefore, the final shape of water molecule is bent-shape.
Learn more:
1. Molecular shape around the central atom in the amino acid glycine: brainly.com/question/4341225
2. Balanced chemical equation: brainly.com/question/1405182
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Covalent bonding and molecular structure
Keywords: hybridization, water, geometry, sp3, steric number, 3, p orbital, s orbital, Lewis structure, hybridization of water, central atom, carbon, hydrogen, oxygen, shape, double bond, h2o.
b. energy
c. heat transferred
d. force
Answer:
Explanation:
Formal charge of ICl₂⁻
Formal charge = group no - ( no of non bonding electrons +no of bonds)
In I there are 7 electrons in outermost orbit . If we add one more electrons due to - ve charge on the ion , it becomes eight . This centrally placed iodine forms two single bond with two chlorine atoms on either side.
Each of chlorine atoms also contains 7 valance electrons like iodine.
So formal charge of chlorine
= group no - ( no of non bonding electrons +no of bonds)
= 7 - ( 6 + 1 )
= 0
So formal charge of iodine
= group no - ( no of non bonding electrons +no of bonds)
= 7 - ( 5 + 2 )
=0
Formal charge of ICl₂⁺
In this case , central iodine will have only 6 valence electrons due to absence one electron.
So formal charge of chlorine in ICl₂⁺
= group no - ( no of non bonding electrons +no of bonds)
= 7 - ( 6 + 1 )
= 0
formal charge of iodine in in ICl₂⁺
7 - ( 4 + 2)
= 1
B. reduction
C. substitution
D. condensation
Answer: Option (B) is the correct answer.
Explanation:
When an atom gains electrons then it becomes rich in electrons and therefore it acquires a negative charge.
Also, it is known that a reduction reaction is a reaction in which an element gain electron(s).
For example, is a reduction reaction.
Thus, we can conclude that when nonmetal atoms become negative nonmetal ions then type of reaction which occurs is reduction reaction.
(2) the relative abundance of each naturally occurring isotope of chlorine, only
(3) the atomic mass and the relative abundance of each naturally occurring isotope of chlorine
(4) the atomic mass and the relative abundance of each naturally occurring and artificially produced isotope of chlorine
Answer is: (3) the atomic mass and the relative abundance of each naturally occurring isotope of chlorine.
m(³⁵Cl) = 34.97 amu; the average atomic mass of chlorine-35.
m(³⁷Cl) = 36.97 amu; the average atomic massof chlorine-37.
ω(³⁵Cl) = 75.76% ÷ 100% = 0.7576; fractional abudance of chlorine-35.
ω(³⁷Cl) = 24.24% ÷ 100% = 0.2424; fractional abudance of chlorine-37.
m(Cl) = m(³⁵Cl) · ω(³⁵Cl) + m(³⁷Cl) · ω(³⁷Cl).
m(Cl) = 34.97 amu · 0.7576 + 36.97 amu · 0.2424.
m(Cl) = 35.4548 amu; average atomic mass of chlorine.
The atomic mass of chlorine is determined by both the atomic mass and the relative abundance of each naturally occurring isotope of chlorine. It's based on an average of the masses of the isotopes according to their relative abundance.
To determine the atomic mass of the element chlorine, option (3), both the atomic mass and the relative abundance of each naturally occurring isotope of chlorine is required. The atomic mass of chlorine is not just the mass of one particular atom, or isotope; instead, it's an average of the masses for all the isotopes according to their relative abundance. For instance, Chlorine has two isotopes Chlorine-35 and Chlorine-37. If the relative abundance of Chlorine-35 is 75% and that of Chlorine-37 is 25%, the atomic mass is calculated by the formula [(0.75 x 35) + (0.25 x 37)].
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