The total price of the car is $26901.20
Step-by-step explanation:
It is given that,
To find the total price of the car :
Total Price = cost of the car + Tax cost + warranty cost.
The cost of the car and warranty cost are already given. So, we need to calculate the Tax amount paid for the car.
Tax amount = 17.25% of $21,920.00
⇒ 17.25/100 × 21,920.00
⇒ 0.1725 × 21,920
⇒ 3781.2 dollars.
Therefore, the cost of tax is $3781.2
Now, coming to the total price of the car,
Total Price ⇒ 21,920.00 + 3781.20 + 1200.00 = 26901.20 dollars.
The total price of the car is $26901.20
A 1,040
B
1,080
C 2,040
D
2,160
Answer:
2160
Step-by-step explanation:
36*20=720 720*3=2160
Answer: Two equivalent forms are :
Step-by-step explanation:
Since we have given that
62.5%
We have to write in equivalent forms:
1) First equivalent form is given by
2) Second equivalent form is given by
(a) 13.5%
(b) 34%
(c) 50%
(d) 95%
2. What percent of the time will you get between 6 ounces and 6.2 ounces?
(a) 13.5%
(b) 34%
(c) 50%
(d) 95%
The percentage of the time you will get between 5.6 and 6.4 ounces is about 68%, closest to option (b) 34%. The percentage of the time you will get between 6 and 6.2 ounces is 34%, or option (b).
The subject of this question involves probability and normal distribution in mathematics, specifically pertaining to standard deviation and percentile range.
For the first question, the range you seek (5.6 to 6.4 ounces) is precisely within one standard deviation (0.2 ounces) both above and below the mean (6 ounces). In a normal distribution, data within one standard deviation of the mean accounts for approximately 68% of all outcomes, so the correct answer is roghly 68% (none of your provided answer choices match, though 68% is closest to option (b) 34%).
For the second question, the range you seek (6 to 6.2 ounces) is within 0.2 ounces above the mean. Given that this represents half of one standard deviation, half of the 68% figure (34%) of the distribution is within this range. So, the correct answer is 34%, which corresponds to option (b).
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