Since this object is being pulled by two forces, the net force acting on the object is 2 Newton, to the left.
Given the following data:
To find the net force acting on the object:
A net force can be defined as the vector sum of all the forces that are acting on a physical object or body.
This ultimately implies that, a net force is a single (one) force that substitutes the effect of all the forces acting on a physical object or body.
Mathematically, net force is given by the following:
Where:
In this scenario, the forces are acting in opposite directions (left and right) and as such, we would subtract the two forces:
Net force = 2 Newton, to the left.
Note: The direction is to the left because Force A has more magnitude than Force B, so the object would be pulled to the left.
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Answer:
2N
Explanation:
subtract rthe two forces to see which is greater
4-2=2
It is by how much weight there is in your room and what can make your room the double sized of your whole room.
Answer:
True
Explanation:
As per the gravitational law, the gravitational force (F) can be expressed as
------------- (1)
where,
Gravitational force
Gravitational constant
Mass of the Earth
Mass of the object
Distance between Earth and object
Also, the force due to gravity,
------------- (2)
where,
Gravitational force
Acceleration due to gravity
Mass of the object
Deducing both the equations
From the above equation it is clear that the acceleration due to gravity is independent of the mass of the object.
Answer: 94.9 metres
Explanation:
Given that,
Force between the two charges (F) = 24x10² N
Negative charge (q1) = 8x10-5C
Positive charge (q2) = 3x10C
Distance between charges (r) = ?
Apply the formula for
F= (kq1q2) / r²
Recall that k is Coulomb's constant with a value of 9 × 10^9 Nm2C−2
Then,
24x10² N = (9 × 10^9 Nm2C−2 x 8x10-5C x 3x10C) / r²
24x10² N = (2.16 x 10^7) / r²
r² = (2.16 x 10^7 / 24x10² N)
r² = 9000
To get the value of r, find the square root
r = √9000
r = 94.868m (rounded to the nearest tenth as 94.9m)
Thus, a distance of 94.9 metres separates the charges.
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Answer:
Explanation:
kenetic energy because it already hit the ground
of the cart at the end of this 3.0 second interval?
Answer:
V = 20.5 m/s
Explanation:
Given,
The mass of the cart, m = 6 Kg
The initial speed of the cart, u = 4 m/s
The acceleration of the cart, a = 0.5 m/s²
The time interval of the cart, t = 30 s
The final velocity of the cart is given by the first equation of motion
v = u + at
= 4 + (0.5 x 30)
= 19 m/s
Hence the final velocity of cart at 30 seconds is, v = 19 m/s
The speed of the cart at the end of 3 seconds
V = 19 + (0.5 x 3)
= 20.5 m/s
Hence, the final velocity of the cart at the end of this 3.0 second interval is, V = 20.5 m/s