A psychology professor assigns letter grades on a test according to the following scheme.A: Top 8% of scores

B: Scores below the top 8% and above the bottom 61%
C: Scores below the top 39% and above the bottom 16%
D: Scores below the top 84% and above the bottom 8%
F: Bottom 8% of scores

Scores on the test are normally distributed with a mean of 65.4 and a standard deviation of 9.7. Find the numerical limits for a D grade. Round your answers to the nearest whole number, if necessary.

Answers

Answer 1

Answer: F
B. Scores below the top 8 and above

Answer 2

Answer:

Final answer:

The numerical limits for a D grade in psychology can be calculated using the Z-score formula. The cutoff scores are below the top 84% and above the bottom 8%. Using the mean of 65.4 and the standard deviation of 9.7, the numerical limits for a D grade are 52 to 79.

Explanation:

To find the numerical limits for a D grade, we need to determine the cutoff scores. According to the given scheme, a D grade corresponds to scores below the top 84% and above the bottom 8%. To calculate these cutoff scores, we can use the Z-score formula. The Z-score is calculated as the difference between a score and the mean, divided by the standard deviation. Using the Z-score table, we can find the Z-scores corresponding to the top 8% and the bottom 8%. Finally, we can use the Z-score formula to find the corresponding scores for those Z-scores.

Given that the mean is 65.4 and the standard deviation is 9.7, we can calculate the Z-scores:

Z-score for the top 8% = 1.405

Z-score for the bottom 8% = -1.405

Using the Z-score formula, where X is the score, the mean is 65.4, and the standard deviation is 9.7:

X = Z * standard deviation + mean

For the top 8%:

X = 1.405 * 9.7 + 65.4 = 79

For the bottom 8%:

X = -1.405 * 9.7 + 65.4 = 52

Therefore, the numerical limits for a D grade are 52 to 79 (rounded to the nearest whole number).

Learn more about Cutoff scores for a D grade in psychology here:

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Find the common ratio of the sequence -164, -82, -41, -20.5

Answers

Answer:

r = $(1)/(2)$

Step-by-step explanation:

The common ratio r of a geometric sequence is

r = $(a_(2) )/(a_(1) )$ = $(a_(3) )/(a_(2) )$ = $(a_(4) )/(a_(3) )$ = ......

r = $(-82)/(-164)$ = $(-41)/(-82)$ = $(1)/(2)$

Use the number 382 to write a subtraction equation in which only tens is ungrouped.

Answers

Answer:

382 - 33 = 349

382- 44 = 338

382 - 35 = 347

Step-by-step explanation:

First let's see what ungroup is.

We are given a number 382

If ungroup this number, we get 3 hundreds 8 tens and 2 ones.

This is called ungrouped.

We are asked to write the subtraction equation in which only tens is ungrouped.

So we need to use the number 382 where only tens place should be ungrouped.

Here the tens place value digit is 8, it means there are 8 tens.(8 *10 = 80)

So we need to subtract a number such that tens should be ungrouped in 382.

The number that should have one's place should be greater that 2, then only we can ungroup tens in the number 382.

We can have many such numbers, 33, 34. 35. 36. 39, 43, 44, 45 and so on.

We can use any of those numbers subtract from 382 in which only tens is ungrouped.

382 - 33 = 349

In 33, the ones place is 3 and in 382 ones place is 2. We cannot subtract 3 from 2.

So we ungroup tens, there 8 tens, we take 1 tens and brake into 10 ones.

Now we will have (10 +2 = 12 ones) from 12 ones we subtract 3 ones, so we get 9 on the ones place.

Similarly, we can write many subtraction equation using the number 382 in which only tens is ungrouped.

382- 44 = 338

382 - 35 = 347

and so on.

382-40=342 I think is the answer

65-6..break apart ones to subtract

Answers

sixty-five minus six is equal to fifty-nine

What are the solutions to x3=5−5i in polar forma. 52‾√3cis(23π12)

b. 52‾√3cis(5π4)

c. 50‾‾‾√6cis(23π12)

d. 50‾‾‾√6cis(7π12)

e. 50‾‾‾√6cis(4π3)

f. 50‾‾‾√6cis(5π12)

g. 50‾‾‾√6cis(5π4)

h. 52‾√3cis(7π12)

i. 52‾√3cis(5π12)

Answers

Answer:

$z_1=(5√(2))^(1/3)cis((7\pi)/(12))$

Step-by-step explanation:

To find the roots of the complex number you use the following formula:

$z=re^(i\theta)\n\nz_k= (r)^(1/n)[cos((\theta+2\pi k)/(n))+sin((\theta+2\pi k)/(n))];\ \ k=0,1,2..n-1$ (1)

in this case the polar number in polar form is:

$r=√(5^2+5^2)=5√(2)\n\n\theta=tan^(-1)((-5)/(5))=-45\°$

By replacing in (1) you obtain:

$z_0=(5√(2))^(1/3)cis((-\pi/4+0)/(3))\n\nz_1=(5√(2))^(1/3)cis((-\pi/4+2\pi)/(3))=(5√(2))^(1/3)cis((7\pi)/(12))\n\nz_2=(5√(2))^(1/3)cis((-\pi/4+4\pi)/(3))=(5√(2))^(1/3)cis((15\pi)/(12))$

hence, you have:

h. 52‾√3cis(7π12)

the blue lake trail is 11 3/8 miles long. Gemma has hiked 2 1/2 miles each hour for 3 hours . how far is she from the end of the trail

Answers

It is very important to look at all the information's that are given in the question. Based on those given information's the answer to the question can be easily deduced.
Length of the blue lake trail = 11 3/8 miles
= 91/8 miles
Distance hiked by Gemma per hour = 2 1/2 miles
= 5/2 miles
Then
Distance hiked by Gemma in 3 hours = (5/2) * 3 miles
= 15/2 miles
Then
Distance from the end of the trail = (91/8) - (15/2) miles
= (91 - 60)/8 miles
= 31/8 miles
= 3 7/8 miles
So it can be concluded from the above deduction that the distance that is still left for Gemma to cover the trail is 3 7/8 miles. I hope there is nothing complicated in the procedure for you to not understand.

Equation for the points (3,8) (2,6) on slope

Answers

$(8-6)/(3-2) = (2)/(1)=4$

The slope is 2

y=2x + b

Plug in a point to solve for b
8 = 2(3) + b

8 = 6 + b
b = 2

The equation is y = 2x + 2

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