Answer:
Step-by-step explanation:
The initial temperature difference of 72 -34 = 38 °F is reduced to a difference of 72 -41 = 31 °F after 35 minutes. The exponential term in the temperature expression could have the factor ...
(31/38)^(t/35) = e^(-kt)
Taking the natural log, we find ...
(t/35)ln(31/38) = -kt
k = ln(38/31)/35 ≈ 0.00581711
To the nearest thousandth, this is ...
k ≈ 0.006
Using this in the equation for temperature, we have ...
T = 72 -38e^(-0.006t)
Filling in the desired value for t (80), we find the turkey temperature after 80 minutes to be about
T = 72 -38e^(-.006×80) = 72 -38e^-.48 ≈ 48.49
T ≈ 48 °F
The value of k is about 0.006, and the turkey temperature is about 48 °F.
Answer:
h/24=d is the right answer if you dont want to read a long step by ster explanation
what is the length in kilometeres
Answer:
A = 62.5
Step-by-step explanation:
I would break this up into two easier cases. the square at the top where three vertices are A,B, and C. and then the triangle for the rest of the area. we can use the distance formula to find the side length of the square.
sqrt((y2-y1)^2 + (x2-x1)^2)
sqrt((5-2)^2 + (-1-3)^2)
sqrt(3^2 + (-4)^2)
sqrt(9 + 16)
sqrt ( 25)
5
so the area of the square is 5^2 =25
now for the triangle. the formula for the area of a triangle is (1/2)bh.
so we can plug in our b=5, but we need to find h.
we use the distance formula between point A and D to find the distance to be 20, but we have to subtract the 5 we already counted in the area of the square. so the height is 15.
so The triangle has area (1/2)×5×15
37.5.
add the two areas together and we get our answer
25+37.5 = 62.5
2. Below, fill in the ratio table for up to five (5) lawns
3. Graph the ordered pair, create a number scale for the X and Y axis, label the X and Y
4. axis with a title, connect the points with a line, label the line with the equation.
Please explain your answer for every question, 1-4 and put the answers in order.
PLS HELP ME
Answer:
i dont know how to do the rest but ik the first one is 1:6. this js means that he charges 6 dollars per 1 lawn.