A solution was prepared by dissolving 0.42 mol hexane into 500g CCl4. What is the change in freezing point of this solution? The Kf for CCl4 is 30.0oC/m. The freezing point of CCl4 is -22.92 °C.

Answer:

[H⁺] =  10⁻¹²

It could be the strongest base.

Explanation:

The base is considered to be of highest strength if it has least hydrogen ion concentration or high hydroxide ion concentration.

Generally a stronger base gives more hydroxide ion concentration.

the relation between hydrogen ion and hydroxide ion concentration is

[H⁺][OH⁻]= 10⁻¹⁴

[OH⁻] = 10⁻¹⁴  /  [H⁺]

a) [H⁺] =  10⁻⁹

[OH-] = 10⁻⁵

b) [H⁺] =  10⁻¹¹

[OH-] = 10⁻³

c) [H⁺] =  10⁻¹⁰

[OH-] = 10⁻⁴

d) [H⁺] =  10⁻¹²

[OH-] = 10⁻²

This the highest concentration of hydroxide ion in the given choices so it could be the strongest base.

Na2CO3 Na2O +CO2   CO2 is the answer

When a single compound breaks down into two or more compounds or elements in a chemical reaction then it is known as decomposition reaction.

The chemical symbol for sodium carbonate is .

The decomposition of sodium carbonate is:

The decomposition of sodium bicarbonate, will result in the formation of sodium oxide, and carbon dioxide, .

Hence, carbon dioxide, will produce with sodium oxide, on decomposition of .