For the function y=-3+4cos (5pi/6 (x+4)), what is the minimum value

Answers

Answer 1
Answer:

interval <-1;1>, which means that this function can take values from interval <-7;-1>. The minimum value is -7.

the min of cos (5pi/6(x+4) = -1

so the min of 4cos 5pi/6(x+4 = -4

so the min of -3 + 4 cos 5pi/6(x+4 = -7

How do you find the minimum value?

If the quadratic equation has a positive term, it also has a minimum value. This minimum can be found by graphing the function or by using one of the two equations. If you have an equation of the form y = ax ^ 2 + bx + c, you can use the equation min = c --b ^ 2 / 4a to find the minimum value.

Rearrange the function using basic algebraic rules and solve the value of x when the derivative is zero. This solution provides the x-coordinates of the vertices of the function where the maximum or minimum values ​​occur. Convert to the original function and solve to find the minimum or maximum value.

Learn more about the function at

brainly.com/question/10439235

#SPJ2

Answer 2
Answer:

Answer:

-7

Step-by-step explanation:

A P E X


Related Questions

Alex, Sara and Henry share £112 in a ratio 3:3:2. How much money does each person get?
Patty is 50 mi. due north of Todd. Emma is due east of Todd. The angle between the direction of the shortest distance from Emma and Patty and due east is 40°. To the nearest mile, how far is Emma from each person?
Determine the derivative of the following and leave the answer with positive exponentsAy/ax if y=5x+√x to the exponent 5/2x²
Heather sampled the ages of 50 randomly selected people that frequented a store and obtained a mean of 24. She constructed a 95% confidence interval which was (19.1, 28.9). What is the margin of error?A) 2.5 years B) 4.9 years C) 5 years D) 6.7 years
A square is shown below. Which expression can be used to find the area, in square units, of the shaded triangle in the square? A square with a side length of 4 units is shown. A diagonal is drawn with one section shaded inside the figure. (5 points) fraction 1 over 2 ⋅ 4 ⋅ 4 fraction 1 over 4 ⋅ 4 ⋅ 4 fraction 1 over 2 ⋅ 2 ⋅ 2 fraction 1 over 4 ⋅ 2 ⋅ 230 points :)

Geometry A Problem! Help! Line AC

Answers

the formula is:  (AB +BC) * BC = EC*DC
 now fill in the numbers that are given:

(AB +6)*6 = 12*5

(AB+6)*6 = 60

6AB +36 = 60

6AB = 24

AB = 24/6

AB = 4

AC = AB +BC
AC = 4 + 6

AC = 10


Blux17help!
Miguel drove for 8 hours at a constant rate. He drove a total of 424 miles.

Donna also drove at a constant rate. The table shows the number of miles she had driven in different numbers of hours.

How do the unit rates compare?


Miguel has a (blank) unit rate of change than Donna because(blank) is greater than(blank)

Answers

Answer:

Miguel has a  

greater

unit rate of change than Donna because  

53 mph

is greater than  

48 mph

Step-by-step explanation:

424/8 =53

(288 - 144)/(6 - 3) = 144/3 = 48

Miguel has a greater rate  than Donna by 5 miles per hour.

Lizzie and Jane share 2690 beads equally between them. They crejewellery items to sell at the school fayre. Jane needs 7 beads per
item and Lizzie needs 8 beads per item. Who, if anyone, will have me
most number of beads left over?​

Answers

Answer:

both of them would have the same amount of beads left over

Step-by-step explanation:

Divide 2690 by 2 = 2690/2 = 1345

divide 1345 by 7 = 192

this remains 1

divide 1345 by 8 = 168

this remains 1

Jillian is selling boxes of cookies to raise money for her basketball team. the 10 oz. box costs $3.50, while the 16 oz. box costs $5.00. at the end of one week, she collected $97.50, selling a total of 24 boxes. the system of equations that models her sales is below.x y= 24

3.50x 5.00y = 97.50

solve the system of equations. how many 10 oz. boxes were sold?

6
9
12
15

Answers

Answer:

15

Step-by-step explanation:

If 10 oz. box costs $3.50 and a 16 oz. box costs $5.00 and she collected $97.50 we can represent an expression that relates for how many money Jillian made:

3.5*x+5*y=97.50 (1)

where x is the number of 10 oz. boxes and y is the number of 16 oz. boxes.

She sold 24 boxes therefore:

x+y=24 (2)

We can right equation in terms of y and substitute it into equation 1:

y=24-x (2)

3.5*x+5*(24-x)=97.50

Solve for x:

x=15

Jillian sold 15 10oz. boxes

x + y = 24...y = 24 - x
3.50x + 5.00y = 97.50

3.50x + 5(24 - x) = 97.50
3.50x + 120 - 5x = 97.50
3.50x - 5x = 97.50 - 120
-1.5x = -22.50
x = -22.50/-1.5
x = 15....there were 15 ten oz boxes (x) sold

There are 88 girls and 96 boys in the sixth-grade what is the rate of girls to boysA- 88 girls for every 96 boys
B- i girl for every 1.09 boys
C- 44 girls for every 48 boys
D- 11 girls for every 12 boys

Answers

The correct option is D. 11 girls for every 12 boys.

We need to determine the ratio of the number of girls to the number of boys.

Given:

Number of girls = 88

Number of boys = 96

The ratio of girls to boys can be represented as "girls : boys."

To simplify the ratio, we can divide both the number of girls and the number of boys by their greatest common divisor (GCD). In this case, the GCD of 88 and 96 is 8.

Dividing both numbers by 8, we get:

Number of girls (after dividing) = 88 ÷ 8 = 11

Number of boys (after dividing) = 96 ÷ 8 = 12

So, the simplified ratio of girls to boys is 11 : 12.

Now, let's check which option matches the simplified ratio:

A. 88 girls for every 96 boys (Does not match)

B. 1 girl for every 1.09 boys (Does not match)

C. 44 girls for every 48 boys (Does not match)

D. 11 girls for every 12 boys (Matches)

The correct option is D. 11 girls for every 12 boys.

Learn more about Ratios here:

brainly.com/question/32531170?

#SPJ2

Answer:

There are 11 Girls for every 12 Boys in the sixth-grade class

Step-by-step explanation:

For this problem, you want to take the original rate which is 88 girls / 96 boys.

Once you have that number, you want to divide both sides by 8.

88/96 = 11/12

The relationship between x and y is represented by the table below. Which equation represents thistable?
Х
y
1
6
3
10
4
12.
5
14
A y = x +5
By = 2x + 4
C y = 3x + 3
D
Not Here

Answers

Answer is D not here