56Fe3+ is an iron ion with a charge of +3, meaning it has 23 electrons after 3 electrons are lost from the uncharged state. It loses the 4s2 electrons first, then one of the 3d electrons.
The student's question refers to 56Fe3+. 56Fe3+ is an iron ion with a charge of +3, which means it has lost three electrons. Understanding the Electron configuration is vital here. Normally, iron (Fe) has 26 electrons as its atomic number is 26. Each electron has a negative charge. But in 56Fe3+, 3 electrons are lost; hence, it will have 23 electrons.
Let's look further into this. The electron configuration of an uncharged Fe atom is 1s²2s²2p6 3s²3p6 4s²3d6. The iron atom loses the 4s2 electrons first (becoming Fe2+), then one of the 3d electrons (becoming Fe3+ or 56Fe3+ as indicated in the question).
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Answer : 3 substance will have 3 mole ratios to be written for a chemical reaction.
Explanation : The mole ratio can be defined as the ratio between the amounts in moles of any two or more compounds involved in a chemical reaction.
It can be determined by comparing the coefficients the formulas of a balanced chemical equation. It is also known as the molar ratio or mole-to-mole ratio.
Hence, when 3 substances are involved in a chemical reaction 3 mole ratios can be written for it.
Li-6 mass = 6.015121amu
Li-7 mass = 7.016003amu
Lithium Mass = 6.94049amu
What is percent abundance of Li-6?
I know that there is an equation:
6.9409 = (% Abundance Li-6 * Weight of Li-6) + (% Abundance Li-7 * Weight of Li-7)
I don't know how to use it.
Answer: This is in the assumption that these are the only 2 isotopes. This means that:
abundance of Li-6 = X
abundance of Li-7 = 1-X
Hence from your equations
6.9409 = (X * 6.015121amu) + ((1-X) * 7.016003amu)
Solve for X = 0.075 or 7.50%
Explanation:
Answer:
Iridium becomes superconducting at extremely low temperatures, and its critical temperature (Tc) for superconductivity is approximately 0.11 Kelvin (K), or 0.11°C.
Explanation:
Given that the critical temperature is given to two significant digits (0.11), your answer should also have two significant digits. Therefore, the temperature at which iridium becomes superconducting is approximately 0.11°C.
Answer:
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Explanation: