Raphael paid $652 for a camera during a 20% off sale. What was the camera's regular price? Please work the problem and show your work so I can understand it better.

Answers

Answer 1

Answer: $x-\ regular\ price\n\nx-(20\%x)=652\n\nx-(0,2*x)=652\n\nx-0,2x=652\n\n0,8x=652\ \ \ \ |divide\ by\ 0,8\n\nx=815\n\nCamera\ earlier\ cost\ 815\$.$

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Plot the intercept to graph the equation x+5y=5

Answers

what grade are you in because if you are in elementary you aian't learning this

Write 2/3 and 3/4 as a pair of fractions with a common denominator

Answers

in short simply we "multiply one fraction's top and bottom by the other's denominator", so let's do so,

$\bf \cfrac{2\cdot 4}{3\cdot 4}\implies \boxed{\cfrac{8}{12}}\qquad \qquad \qquad \qquad \qquad \cfrac{3\cdot 3}{4\cdot 3}\implies \boxed{\cfrac{9}{12}}$

A dartboard has a diameter of 18 inches.What are its radius and circumference?

Answers

Diameter of the dartboard as given in the question = 18 inches
Then
Radius of the dartboard will be = 18/2 inches
      = 9 inches
We already know that
Circumference of a circle = 2πr
We also know that the value of π = 3.14159
Then
Circumference of the dartboard = 2 * 3.14159 * 9 inches
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There are 3 times as many used bikes in the showroom as there as new bikes. There are 164 bikes total in the showroom. How many new bikes are in the showroom

Answers

Number of new bike in showroom is 41 bikes.

Given that;

Total number of bikes in showroom = 164 bikes

3 times Number of new bike = Number of old bikes

Find:

Number of new bikes in showroom

Computation:

Assume;

Number of new bike = a

So,

Number of old bike = 3a

So,

a + 3a = 164

4a = 164

a = 41

So,

Number of new bike = 41

Learn more:

brainly.com/question/16918813?referrer=searchResults

Answer:

Step-by-step explanation:

There are 3 times as many used bike as new bike. For the problem to work you have to include the used bikes and the new bikes. So you divide 164 by 4 instead of three.

So 164/3=41

Please help me asap!!!

Answers

Answer:

B) AD=30m

Step-by-step explanation:

AG:AD=2:3

Given AG=20m

Then;

$20:AD=2:3$

Rewrite as ratio to get;

$(20)/(AD)=(2)/(3)$

Cross multiply;

$2|AD|=3* 20$

$2|AD|=60$

Divide through by 2;

$|AD|=30$

List all the subsets of each set:

{a,e,i, o}

Answers

$\{\}, \{a\}, \{e\}, \{i\}, \{o\}, \{a, e\}, \{a, i\}, \{a, o\}, \{e, i\}, \{e, o\}, \{i, o\}, \{a, e, i\},\n \{a, e, o\}, \{a, i, o\}, \{e, i, o\}, \{a, e, i, o\}$

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