Question:
Find the probability of getting a doublet in a throw of a pair of dice.
Answer:
The probability is 1 out of 6.
Explanation:
There are a total of 6 possibilities that you get a doublet, which is {1, 1}, {2, 2}, {3, 3}, {4, 4}, {5, 5}, and {6, 6}.
The total possibilities of throwing a dice are 6 possibilities for the first dice, and 6 possibilities for the second dice. Which results in a total of 6 × 6 = 36 possibilities available.
Probability = Possibilities of getting doublet ÷ Total possibilities = 6 ÷ 36 = 1 ÷ 6.
Hopefully this answer will help you.
For this case we have the following expression:
We can rewrite the expression by factoring
Rewriting the expression we have:
Then, using the distributive property for the negative sign we have:
Thus, we have that one of the factors of the given expression is:
12-7x
Answer:
A factor of the given expression is:
12-7x
option 3
Answer: Option 3(C)
Right on ED 2020, Good luck!
Answer:
3x + 3
Step-by-step explanation:
(2x - 2) + (x + 5)
Combine like terms:
2x + -2 + x + 5
(2x + x) + (-2 + 5)
3x + 3
Hope you learned from this answer!