An object of mass 2 kg has a linear momentum of magnitude 6 kg • m/s. What is this object’s kinetic energy?

Answers

Answer 1

Answer:

The kinetic energy of the object with a mass of 2kg has a linear momentum of 6kgm/s is 9 joules.

What is kinetic energy?

Kinetic energy is the energy obtained when the body is in motion. It is obtained from the product of mass and velocity. The SI unit of Kinetic energy is Joule(J).

K.E = 1/2 (mv²) where m is the mass of the object and its unit is the kilogram. v is the velocity of the object and its unit is m/s. The momentum of the object is obtained from the product of mass and velocity.

From the given,

Mass of the object (m) = 2 kg

Linear momentum of the object = 6 kg.m/s

Linear momentum (p) = m×v (m = mass of the object, v= velocity of the object)

v = p / m

= 6 / 2

= 3 m/s

The velocity of the object = 3 m/s

Kinetic energy = 1/2 (mv²)

K.E = 1/2 (2×3×3)

= 9 joules

Thus the kinetic energy of the object is 9 joules (J).

To learn more about Kinetic energy ;

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Answer 2

Answer: Well, the speed is 3 m/s, while the kinetic energy is $(2*3*3)/(2)$ , that is, 9 joules.

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How do you calculate the initial speed given time and displacement?The question is: The longest kick in CFL history was 83.2m. If the ball remained in the air for 4.12s, determine its initial speed.
I calculated it several times and got the same answer, 40.38m/s, but the textbook says it's 28.6m/s.

Answers

Let's first find the velocity in the x-direction which is constant.
$d = vt \n v = (d)/(t) \nv = (83.2m)/(4.12s) \n v= 20.2m/s$

Now, we need the velocity in the y-direction
$d = v_(o)t + (1)/(2)a t^(2) \n d - (1)/(2)at^(2) = v_(o)t\nv_(o) = (0 - (1)/(2)(-9.81)(4.12)^(2))/(4.12)\nv_(o) = 20.2m/s$

Finally, we need to put the two velocities together using pythagorean theorem
$v_(t)^(2) = v_(x)^(2) + v_(y)^(2)$
$v_(t) = \sqrt{20.2^(2) + 20.2^(2)}$
v = 28.6m/s

Caleb likes to take his fork and bang it on different surfaces to make different sounds. Based on Piaget's substages, we can assume that Caleb is: a) In the sensorimotor stage b) In the preoperational stage c) In the concrete operational stage d) In the formal operational stage

Answers

Based on Piaget's substages, we can assume that Caleb is: b) In the preoperational stage.

I am really struggling with this question because I can't find anything on aphelion and perihelion, it's not a topic we went over because it is an extra assignment. 4. How far away from the sun was Mercury at aphelion? On what day did aphelion occur?
5. How far away from the sun was Mercury at perihelion? On what day did it occur?
6. How many days elapsed between aphelion and perihelion? What percent of the time to complete one orbit was this?
7. What was the average radius of Mercury in its orbit that you calculated? How does it compare to the accepted value of 0.387 AU? Calculate the percent error using the following equation. Show your work.

If someone could explain it to me I would really appreciate it!

Answers

I have a strange hunch that there's some more material or previous work
that goes along with this question, which you haven't included here.

I can't easily find the dates of Mercury's extremes, but here's some of the
other data you're looking for:

Distance at Aphelion (point in it's orbit that's farthest from the sun):
69,816,900 km
0. 466 697 AU

Distance at Perihelion(point in it's orbit that's closest to the sun):
46,001,200 km
0.307 499 AU

Perihelion and aphelion are always directly opposite each other in
the orbit, so the time between them is 1/2 of the orbital period.

Mercury's Orbital period = 87.9691 Earth days

1/2 (50%) of that is 43.9845 Earth days

The average of the aphelion and perihelion distances is

1/2 ( 69,816,900 + 46,001,200 ) = 57,909,050 km
or
1/2 ( 0.466697 + 0.307499) = 0.387 098 AU

This also happens to be 1/2 of the major axis of the elliptical orbit.

The gravitational potential energy of an object Is always measured relative to the

Answers

The gravitational potential energy of an object Is always measured relative to the height of the object. It has the equation equal to mass PE = mgh where PE is the potential energy, m is the mass of the object, H is the height of the object and g is the acceleration due to gravity.

The gravitational potential of an object is always measured relative to reference level/another point

Further explanation

Energy is the ability to do work. Energy can change from one energy to another

Gravitational potential energy is the energy that an object has because of its position

The potential energy can be formulated:

Ep = m. g. h

E = potential energy of an object, joule

m = object mass, kg

g = gravity acceleration, m / s2

h = height of an object, m

The higher the object from the surface of the earth and the greater the mass, the greater the potential energy of the object. Earth's gravity also affects the potential energy of objects

Potential energy itself includes mechanical energy

Em = Ek + Ep

Em = mechanical energy

Ek = kinetic energy

Ep = potential energy

The amount of kinetic energy and potential energy of objects is always constant