A bag contains 88 red, 66 orange, and 99 green jellybeans. What is the probability of reaching into the bag and randomly withdrawing 1212 jellybeans such that the number of red ones is 22, the number of orange ones is 44, and the number of green ones is 66? Express your answer as a fraction or a decimal number rounded to four decimal places.

Answers

Answer 1
Answer:

Answer:

P ( 2 R , 4 O , 6 G ) = 0.0261

Step-by-step explanation:

Given:

- Red beans = 8

- Orange beans = 6

- Green beans = 9

Find:

What is the probability of reaching into the bag and randomly withdrawing 12 jellybeans such that the number of red ones is 2, the number of orange ones is 4, and the number of green ones is 6?

Solution:

- The question requires the number of selection of 12 jellybeans we can make from total available such that out of those 12 we choose 2 Red, 4 Orange and 6 Green.

- For selection we will use the combinations. So to choose 2 Red from 8; Choose 4 Orange from 6 and 6 green from 9 available. The number of possible outcomes with such condition is:

          Outcomes ( 2 R , 4 O , 6 G ) = 8C2 * 6C4 * 9C6

                                                         = 28*15*84

                                                         = 35280

- The total number of outcomes if we randomly select 12 beans irrespective how many of each color we select from available 23 we have:

          Outcomes ( Select 12 from 23 ) = 23C12

                                                               = 1352078

- Hence, the probability for the case is given by:

P ( 2 R , 4 O , 6 G ) = Outcomes ( 2 R , 4 O , 6 G ) / Outcomes ( Select 12 from 23 )

P ( 2 R , 4 O , 6 G ) = 35280 / 1352078 = 0.0261


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How old am I if 400 reduced by 2 times my age is 244? (answer with steps)

Answers

400 reduced (minus) 2 times my age (2x) is 244 (= 244).

400 - 2x = 244   Subtract 400 from both sides
         -2x = -156   Divide both sides by -2
            x = 78

I am 78 years old.

Can someone help me and let me know if my answer is correct?A large emerald with a mass of 764.3 grams was recently discovered in a mine. If the density of the emerald is 2.76grams over centimeters cubed, what is the volume? Round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point.

276.92

Answers

The answer is 276.92

The density (D) of is quotient of mass (m) and volume (V):
D = (m)/(V)

It is given:
m = 764.3 g
D = 2.76 g/cm³
V = ?

Since:
D = (m)/(V)
⇒ V= (m)/(D)= (764.3g)/(2.76g/cm^(3) ) = 276.92 cm ^(3)

Therefore, the volume of the emerald is 276.92 cm² and your answer is correct.

Answer:

276.92 cubic cm.

Step-by-step explanation:

Given :

A large emerald with a mass of 764.3 grams was recently discovered in a mine.

The density of the emerald is 2.76gm/cm^3

To Find: what is the volume?

Solution:

Density =2.76gm/cm^3

Mass = 764.3 grams

Volume=(Mass)/(Density)

Volume=(764.3)/(2.76)

Volume=276.92

Hence the volume of large emerald is 276.92 cubic cm.

If each number is rounded to the nearest hundred, which statement is true? A = 196.3 + 238.89 + 384.92 B = 329.11 + 288.06 + 106.4

Answers

A = 196.3 + 238.89 + 384.92 rounded to the nearest hundred
A = 200 + 200 + 400 = 800

B = 329.11 + 288.06 + 106.40 rounded to the nearest hundred
B = 300 + 300 + 100 = 700

800 is greater than 700. Thus, A > B. 

Answer:

800 is greater than 700. Thus, A > B.

Step-by-step explanation:

Find x in picture below.
a. 4
b. 6
c.12

Answers

Answer:

C.12

Step-by-step explanation:

Apply the formula for tangent-secant

Let the cord length inside the circle to be y

According to the tangent-secant relation

(3+y)/6 = 6/3

cross multiply

3(3+y)=6*6

9+3y=36

3y=36-9

3y=27

y=27/3

y=9

Distance x = y+3

x=9+3=12

A box contains 13 red blocks, 8 orange blocks,9 green blocks,and 10 blue blocks . Shelly randomly chooses a block from the box. What is the probability that the block will not be green ? write answer as decimal

Answers

13\ red+8\ orange+9\ green+10\ blue=40\ all\ blocks\n\n
Before we find the total number of blocks 13+8+9+10=40 blocks

-

chance of having the green block   13+8+10/40 

31/40=0.775 present as  Take it easy

Find the interquartile range of these data.

5, 12, 9, 8, 6, 2, 6

Answers

Answer: 7

Step-by-step explanation: