6
in
12 in
What’s the area

Answers

Answer 1
Answer:

Answer:

72 in^2

Step-by-step explanation:

6 x 12 = 72

Answer 2
Answer:

Answer:

well if your talking about a square, then the answer would be 72


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your friend offers to pay you $10 plus $2 per day if you will watch his dog while he’s on vacation. Ant hot her friend offers you $15 plus $1 per day to watch her dog during the same time. You cannot do both jobs. Tell which job you would choose and explain why.

Answers

Answer:

you didn't say for how many days

Answer:

You should choose Ant hot because he offers the bigger/more money for the same time.

Step-by-step explanation:

Simplify the radical
√3c^2 / √27
show all steps.

Answers


√2727Rewrite 2727 as 32⋅332⋅3.32⋅332⋅3Pull terms out from under the radical.3√333The result can be shown in both exact and decimal forms.Exact Form:3√333Decimal Form:5.19615242…5.19615242…

Can anyone tell me everything there is to know about functions?How they're solved
Its formula
etc.
(30 pts)

Answers

Answer:

function

A set of ordered pairs where each first element is paired with one and only one second element and no element in either pair is without a partner.

Step-by-step explanation:

Question 1: Calculate the slope, x-intercept and y-intercept of a linear equation, f(x) = 5x + 4 ?

Solution:

Given,

f(x) = 5x + 4

The general form of a linear equation is,

f(x) = mx + c

So,

Slope = m = 5

Substitute f(x) = 0,

0 = 5x + 4

5x = -4

x = −45

The x-intercept is (−45, 0)

Substitute x = 0,

f(x) = 5(0) + 4

f(x) = 0 + 4

f(x) = 4

The y-intercept is (0,4)

Answer:

function junction

Step-by-step explanation:

If x and y are real numbers such that x > 1 and y < −1,then which of the following inequalities must be true?
A. x/y> 1
B. |s|^2 > |y|
C. x/3− 5 > y/3 − 5
D. x^2 + 1 > y^2 + 1
E. x^(−2) > y^(−2)

Answers

x > 1\ \wedge\ y < -1\n\nA.\ (x)/(y) > 1-FALSE;example:x=2;\ y=-2\ then\nL=(2)/(-2)=-1;R=1;\ L < R\n\nB.\ |x|^2 > |y|-FALSE;example:x=2;\ y=-6\ then\nL=|2|^2=2^2=4;R=|-6|=6;\ L < R\n\nC.\ (x)/(3)-5 > (y)/(3)-5-TRUE;(x)/(3)-5 > (y)/(3)-5\to(x)/(3) > (y)/(3)\to x > y

D.\ x^2+1 > y^2+1-FALSE;example:x=2;\ y=-3\ then\nL=2^2+1=4+1=5;R=(-3)^2+1=9+1=10;L < R\n\nE.\ x^(-2) > y^(-2)-FALSE;example:x=3;\ y=-2\ then\nL=3^(-2)=(1)/(9);R=(-2)^(-2)=(1)/(4);\ L < R

1. If 1 cm represents 10 m, what are the actual measurements of the gym includingthe closet?
2. What are the actual measurements of the closet?
3. If 1 cm represents 12 m, what are the actual measurements of the gym including
the closet?
4. What is the area of the gym?

Answers

Answer:

1.  50 meters by 40 meters

2.  20 meters by 10 meters

3.  60 meters by 48 meters

4. DrawingGym Area = 18 sq. cm. and  Actual Gym Area = 2592 sq. m.

Step-by-step explanation:

1.

The drawing length of the GYM+CLOSET area is:

5 cm by 4 cm

Since 1 cm represents 10 m in real life, we can say the real life dimensions are:

5cm * 10 = 50 meters

4 cm * 10 = 40 meters

THe actual measurements of gym (including closet):

50 meters by 40 meters

2.

The drawing measurement of the closet would be:

2 cm length given and 1 cm width given

Since we know 1 cm represents 10 meters in real life, the actual measurements would be:

1cm * 10 = 10 meters

2 cm * 10 = 20 meters

The actual dimensions of closet:

20 meters by 10 meters

3.

Gym + Closet area is still 5cm by 4cm in the drawing.

Now, the scale changes. The new scale is:

1cm = 12 meters

So,

5cm * 12 = 60 meters

4 cm * 12 = 48 meters

The actual measurement of Gym and Closet (new scale):

60 meters by 48 meters

4.

First, let find the area of the gym. This will be total area - closet area

We know area of rectangular figure is Length * Width

SO,

Total Area = 5 * 4 = 20

Closet Area = 2 * 1 = 2

Thus,

Gym Area = 20 - 2 = 18

Gym Area = 18 sq. cm.

In real life (1cm = 12 m -- new scale), Gym Area would be:

Gym Area = 18cm^2*(12m)/(1cm)*(12m)/(1cm)=18*12*12m^2=2592m^2

Actual Gym Area = 2592 sq. m.

Something that equals to 38 in addition

Answers

23+15=38

so basically that is super easy to kno, i ddi it for you because i need cins asap