Find the 8th term of the geometric sequence -324, -108, -36, -12, . . .

Answers

Answer 1
Answer:

Answer:

the 8th term is 0.148148148148...

Step-by-step explanation:

-108÷(-324)=0.333333333333 = 1/3

(-36)÷(-108)=0.333333333333

(-12)÷(-36)=0.333333333333

then the common ratio of the sequence is 1/3

then

the 5th term is 12×(1÷3) = 4

the 6th term is 4×(1÷3) = 1.333333333333

the 7th term is 1.333333333333×(1÷3) = 0.444444444444

the 8th term is 0.444444444444×(1÷3) = 0.148148148148


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Consider the decimal 0.101001000100001000001 do you think this decimal represents a rational number? Why or why not.

Answers

this decimal does not represent a rational number because rational numbers are whole numbers, numbers that can be written as a fraction

Which of the following could be the ratio of the length of the longer leg of a 30-60-90 triangle to the length of its hypotenuse? Check all that apply

Answers

The ratio of the longer leg to the hypotenuse of a 30-60-90 triangle is option √3 : 2.

How did we arrive at the value?

In a 30-60-90 triangle, the longer leg is opposite the 60-degree angle and the hypotenuse is opposite the 90-degree angle.

Make x the length of the shorter leg, then the longer leg is x√3 and the hypotenuse is 2x.

So the ratio of the longer leg to the hypotenuse is:

x√3 : 2x

Simplifying, we get:

√3 : 2

Therefore, the ratio of the longer leg to the hypotenuse of a 30-60-90 triangle is √3 : 2.

So the correct answer is (A).

learn more about hypotenuse:brainly.com/question/2217700

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Last Month the electric meter reading was 7985 kWh. This month the reading was 8328 kWh. If electricity costs P3.40 per kWh,how much will I pay?

Answers

8328kWh-7985kWh=343kWh\n\n343\ *\ 3.40=1166.20\leftarrow answer
8328-7985=343\n 343\cdot\pounds3.40=\pounds1166.2

What is 0.008 as a fraction

Answers

The answer is 1/125. Just use a calculator if u do not believe me.

What is the answer to this question

Answers

ok so first find the important stuff.

1. 6 chalkboards per grade
2. 3 grades
3. $98 per chalkboard 

then you multiply 6 by 3 to get 18 
next you multiply 18 by 98 to get 1764 

So your answer is ........($1764.00) 

hope this helps hope i am brainliest i need 1 more

Josh used a standard deck of 52 cards to conduct an experiment. Half of the cards in the deck were red. The other half were black. Josh predicted that he would choose a red card in 4 out of 8 trials. When he conducted the experiment, he actually chose a red card 6 out of 8 times. Which explains the most likely reason for the discrepancy between Josh’s predicted and actual results?A.He incorrectly predicted the number of times he would choose a red card.
B.He incorrectly determined the actual number of times he chose a red card.
C.He used too few trials for the sample space.
D.He used too many trials for the sample space.

Answers

Answer: C. He used too few trials for the sample space.


Step-by-step explanation:

Given: Josh used a standard deck of 52 cards to conduct an experiment.

As half of the cards in the deck were red.

If we take sample space= 52 cards

Then probability of getting a red card=(1)/(2)

But Josh took 8 cards as sample space which is not enough for the sample space.

therefore, C. is the right answer. "He used too few trials for the sample space."


Answer:

Option C - He used too few trials for the sample space.

Step-by-step explanation:

Given: Josh used a standard deck of 52 cards to conduct an experiment. Half of the cards in the deck were red. The other half were black.

Josh predicted that he would choose a red card in 4 out of 8 trials.

When he conducted the experiment, he actually chose a red card 6 out of 8 times.

To find : Which explains the most likely reason for the discrepancy between Josh’s predicted and actual results?

Solution :

Sample space = 52 cards

As half of the cards in the deck were red.

Probability of getting a red card is (1)/(2)

He predict and conduct to choose a red card out of 8 trials which is not enough for the sample space.

Therefore, Option C is correct.

He used too few trials for the sample space.