The temperature of the coffee after 16 minutes is 134 degrees and after 1.3 minutes the coffee be 100 degrees.
A differential equation is an equation that contains one or more functions with its derivatives.
A cup of coffee at 181 degrees is poured into a mug and left in a room at 66 degrees.
After 6 minutes, the coffee is 139 degrees.
Assume that the differential equation describing Newton's Law of Cooling is (in this case) dT/dt=k(T-66).
T=∫k(t-66)dt
=k(t²/2-66)+c
When t=0 and T=181
181=k(0-66)+c
181=-66k+c
when t=6, T=139
139=k(6²/2-66)+c
139=-48k+c
-42=-18k
Divide both sides by 18
k=7/3
139=-48×7/3+c
c=139+112=251
T=7/3(t-66)+251
The temperature of the coffee after 16 minutes
T=7/3(16-66)+251
T=7/3(-50)+251
T=134 degrees
After how many minutes will the coffee be 100 degrees
100=7/3(t-66)+251
100=7/3t-7/3(66)+251
100=7/3t-154+251
100=7/3t+97
100-97=7/3t
3=7/3t
9/7=t
1.3=t
Hence, the temperature of the coffee after 16 minutes is 134 degrees and after 1.3 minutes the coffee be 100 degrees.
To learn more on Differentiation click:
#SPJ5
Answer:
Step-by-step explanation:
What is the interquartile range of the data?
Answer: 4
Step-by-step explanation:
First arrange the given data in ascending order :-
Number of terms = 9
Second quartile =Median=
Now, the first quartile=The median for the lower half of data
= Mean of 2nd term and 3rd term
The third quartile =The median for the upper half of data
= Mean of 7th term and 8th term
Now, Interquartile range =
Hence, the interquartile range of the data =4.
Answer:
(C) 4
Step-by-step explanation:
♥☺
b. 164
c. 184
d. 164 1/3
3(2x+1)=2(x+1)+1
Step 1:Simplify both sides of the equation
(3)(2x)+(3)(1)=(2)(x)+(2)(1)+ -(distribute)
6x+3=2x+2+1
6x+3=(2x)+(2+1) -(Combine Like Terms)
6x+3=2x+3
Step 2: Subtract 2x from both sides
6x+3-2x=2x+3-2x
4x+3-3=3-3
4x÷4=0÷4
x=0
Answer & Step-by-step explanation:
Make a fraction using the numerator:
Simplify the fraction. Both the numerator and the denominator are multiples of 3, so divide top and bottom by 3 to the lowest possible integer:
Insert into the equation:
:Done
You can use different numbers too