11. The density of liquid chloroform is 1.48 g/mL. What is its density in units of lb/in?(2.54 cm = 1 in., 2.205 lb = 1 kg)

Answers

Answer 1
Answer:

The density of the liquid chloroform is 0.0535 lb/in³.

The given parameters:

  • Density of the liquid, = 1.48 g/mL

The density of the liquid chloroform in pounds per cubic inches (lb/in³) is calculated by multiplying with the appropriate equivalent units as demonstrated below;

\rho = 1.48 \ (g)/(mL) * (1 \ mL)/(cm^3) * ((2.54cm)^3)/((1\ in)^3) * (1 \ kg)/(1000 \ g) * (2 .205 \ lb)/(1 \ kg) = 0.0535 \ lb/in^3

Thus, the density of the liquid chloroform in pounds per cubic inches is determined to be 0.0535 lb/in³.

Learn more about conversion of density here: brainly.com/question/13858006

Answer 2
Answer:

Answer:

5.35*10^-2\ lb/in^3

Explanation:

Given density of chloroform is 1.48 g/mL

We need to find the density in lb/in^3

Also, we have given 2.54 cm = 1 in and 2.205 lb = 1 kg

We know 1ml=1cm^3

Also, 2.54 cm = 1 in

2.54^3\ cm^3=1\ in^3\n16.38\ cm^3=1\ in^3\n16.38\ cm^3=16.38\ ml=1\ in^3

And 1000 g = 1 kg

1\ g=(1kg)/(1000)\n\n1\ kg=2.205\ lb\n\n1\ g=(2.205\ lb)/(1000)=2.205*10^(-3)\ lb

Now we will plug

1\ ml=(1)/(16.38)\ in^3 \n\nAnd\ 1\ g=2.205*10^-3\ lb

So,

1.48\ (g)/(ml)=1.48* 2.205*10^(-3)(lb)/((in^3)/(16.38) )\n \n=1.48*2.205*16.38*10^(-3)(lb)/(in^3)\n =5.35*10^(-2)(lb)/(in^3)


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Answers

Answer:

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Explanation:

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Answers

Answer:

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Answers

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What are the possible orbitals for n = 3?

Answers

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What are the possible orbitals

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Learn more about orbitals  at

brainly.com/question/20319149

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Answer:The n = 3 shell, for example, contains three subshells: the 3s, 3p, and 3d orbitals. There is only one orbital in the n = 1 shell because there is only one way in which a sphere can be oriented in space.

Explanation:hope this helps:D