The average age of the employees in 2003 is 57.216 years. And, the average age of the employees in 2009 is 59.184 years.
Given that;
The function A(s) given by ,
A (s) = 0.328s + 50
Now for the average age of employees in 2003 and 2009 using the function A(s) = 0.328s + 50, substitute the values of s into the equation.
For the year 2003,
Since s represents the number of years since 1981,
Hence, subtract 1981 from 2003:
s = 2003 - 1981
s = 22
Now substitute this value of s into the function A(s):
A(22) = 0.328 × 22 + 50
A(22) = 7.216 + 50
A(22) = 57.216
Therefore, the average age of the employees in 2003 is 57.216 years.
Similarly, for the year 2009,
s = 2009 - 1981
s = 28
Substituting this value into the function:
A(28) = 0.328 × 28 + 50
A(28) = 9.184 + 50
A(28) = 59.184
Hence, the average age of the employees in 2009 is 59.184 years.
To learn more about the function visit:
#SPJ12
The mathematical problem involves calculating the average age of employees at a company for the years 2003 and 2009 using the linear function A(s), where 'A(s)' represents the average age and 's' is the number of years since 1981. The calculated average ages for the employees in the years 2003 and 2009 are approximately 57 and 59 years, respectively.
The subject is mathematics, specifically linear functions. Based on the equation A(s) = 0.328s + 50, where 'A(s)' represents the average age of the employees and 's' represents the number of years since 1981. In the year 2003, s would be 22 (2003-1981) and in 2009, s would be 28 (2009-1981).
Substituting these values of 's' into the function gives:
For 2003, A(22) = 0.328*22 + 50 = 57.216
For 2009, A(28) = 0.328*28 + 50 = 59.184
Therefore, the average age of the employees at the company in 2003 and 2009 were approximately 57 and 59 years, respectively.
#SPJ11
The work done to lift the coal is 6.8*10^5 ft-lb
Data;
Let the distance (ft) below top of the shaft be represented by x
The weight of the coal to be lifted from mine = 500lb
The work done to lift the coal is
Taking the summation limit
we can take the integration of both sides where x will the range from 0 to 400.
From the calculations above, the work done is 6.8*10^5 ft-lb
Learn more on work done on a lift here;
Answer:
8.2 *10^5 ft lb
Step-by-step explanation:
Wcoal = 800*500 = 400000 = 4*10^5 ft lb
Using a right Riemann sum
The width of the entireregion to be estimated = 400 - 0 = 400
Considering 8 equal subdivisions, then the width of each rectangular division is 400/8 = 50
F(x) = 6(400-y)
Wrope = 50(2100) + 50(1800) + 50(1500) + 50(1200) + 50(900) + 50(600)
+ 50(300) + 50(0) = 420000 = 4.2 * 10^5 ft lb
Note: Riemann sum is an approximation, so may not give a accurate value
work done = Wcoal + Wrope= 4*10^5+ 4.2 * 10^5 = 8.2 *10^5 ft lb
Answer:
a. As given in the question, some towns are located high in the Rockies above the sea level and some are located in the south-central valley of the California below the sea level as well. The meaningful zero does not exists here and the variable of interest is continuous(quantitative). Hence, the elevations can be best described as an interval data.
b. The unemployment rate can not be negative. Therefore, the meaningful zero exist here. Hence, the unemployment rate can be best described as ratio data.
it is
B) ||u+v|| = sqrt ||u||2 + ||v||2
AND
D) ||u+v|| less than ||u||+||v||
check the picture below.
notice, the sum of u+v yields the red vector, and its magnitude is smaller than the sum of the other two green ones.
8
8xy
320
320xy
The greatest common factor of 8x and 40y is 8.
Factors of a number or an algebraic expression are the numbers or expressions which divides the given number evenly.
For example, 10 = 2 × 5
So we can say that 2 and 5 are factors of 10.
Greatest common factor of two or more numbers is the factor which is the greatest among all the common factors of both the numbers.
8x can be prime factorized as,
8x = 2 × 2 × 2 × x
Similarly, 40y can be prime factorized as,
40y = 2 × 2 × 2 × 5 × y
Greatest common factor of both the numbers is the product of the common prime factors of both.
Greatest common factor = 2 × 2 × 2 = 8, which is common to both.
Hence 8 is the greatest common factor of 8x and 40y.
Learn more about Greatest Common Factors here :
#SPJ6
Answer:
8
Hope this helps!
3y=6x+12
y = 7 + 3x
y = 3x + 7
y = mx + b, therefore the y-intercept is 7.
3y = 6x + 12
y = 2x + 4
y = mx + b, therefore the y-intercept is 4.
Answer:
2x squared +1 (-)x squared -7 is
a.) x squared +8
Step-by-step explanation:
:)