Answer:
68% of the incomes lie between $36,400 and $38,000.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = $37,200
Standard Deviation, σ = $800
We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.
Empirical rule:
Thus, 68% of data lies within one standard deviation.
Thus, 68% of the incomes lie between $36,400 and $38,000.
Answer:
total profit margin for all 12 concert is $6,400.
profit margin for all one concert is $533.33
Step-by-step explanation:
Amount of money received for one event = $1700
Total no of concert = 12
Total money received for 12 event = Amount of money received for one event * Total no of concert
Total money received for 12 event = $1700 *12 = $20,400
Total cost of sponsorship = $14,000
Profit margin is the difference money invested and money earned.
here total investment is $14,000
Total money earned is $20,400
Therefore profit margin = money earned - total investment
= $20,400 - $14,000 = $6,400
Therefore total profit margin for all 12 concert is $6,400.
However to calculate profit margin for one concert we can simply divide the total profit margin for all 12 concert by no of concert (i.e 12)
profit margin for one concert = total profit margin for all 12 concert/total no of concert = $6,400/12 = $533.33
profit margin for all one concert is $533.33
Answer:
936
Step-by-step explanation:
Therefore you multiply 6 by 18 = 6×18= 108
1,044 - 108 = 936
So therefore the total is 936
The cost of each ticket before insurance is $156. This is obtained by subtracting the total cost of the insurance from the total amount spent and then dividing by the number of tickets.
The subject of this question seems to be an exercise in elementary algebra. If a family buys 6 airline tickets online and also purchases travel insurance that costs $18 per ticket, then the amount spent on insurance alone is $18 * 6 = $108. We know that the total cost, including the tickets and the insurance, is $1,044. Therefore, to find out the cost of the tickets alone, we subtract the cost of the insurance from the total cost: $1,044 - $108 = $936, which will be the cost for the tickets alone. So, the cost of each ticket is $936 / 6 = $156. Therefore, each ticket cost $156 before insurance.
#SPJ12
A)
17 inches
B)
2.4 inches
o
2.9 inches
D)
3.1 inches
Answer:
B) 2.4 inches
Step-by-step explanation:
The total amount of rain is 28.8 inches over 12 months. To find how much rain falls averagely in one month you need to divide the total by the amount of months. 28.8/12 = 2.4
Answer:
≈ 201
Step-by-step explanation:
V= πr²h/3
V= 3.14*4²*12/3= 200.96 ≈ 201
The volume of the cone is 201.06 units³.
The volume of a cone is given by the formula:
Volume = (1/3) * π * r² * h
where r is the radius of the base and h is the height of the cone.
In this case, r = 4 units and h = 12 units. Using 3.14 for π, we can calculate the volume of the cone as follows:
Volume = (1/3) * 3.14 * 4² * 12
Volume = 201.06 units³
Therefore, the volume of the cone is 201.06 units³.
For such more question on volume
#SPJ3
Answer:
The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.
Step-by-step explanation:
Using Bayes' Theorem
P(A|B) =
where
P(B|A) is probability of event B given event A
P(B|a) is probability of event B not given event A
and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.
For this problem,
Let P(B1) = Probability of machine B1 = 0.3
P(B2) = Probability of machine B2 = 0.2
P(B3) = Probability of machine B3 = 0.5
Let P(D) = Probability of a defective product
P(N) = Probability of a Non-defective product
P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003
P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006
P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010
Likewise,
P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997
P(N|B2) be probability of a non-defective product produced by machine 2 = 1 - P(D|B2) = 1 - 0.006 = 0.994
P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990
For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)
P(B1|N) = = = 0.1138
Hence the probability that a non-defective product is produced by machine B1 is 11.38%.
Answer:
Correct option is:
C. 2
Step-by-step explanation:
We have to find the exponent in the term -3x²
An exponent refers to the number of times a number is multiplied by itself.
Here, x is multiplied to itself 2 times
i.e.
Hence, exponent in the term -3x² is:
2
So, the correct option is:
C. 2