19. Which missing symbol makes theequation true?
10 3–4=9
+
1
X
.

Answers

Answer 1
Answer: The +, as 10+3=13-4=9.

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A rectangle has the length of 22 inches less than 7 times the width. If the area of the rectangle is 3197 square inches, find the length of the rectangle

Answers

The length of rectangle is 139 inches

Solution:

Given that, area of the rectangle is 3197 square inches

Let "L" be the length of rectangle and "W" be the width of rectangle

Also given that rectangle has the length of 22 inches less than 7 times the width

Length = 7 times width - 22

L = 7W - 22

The area of rectangle is given as:

\text {Area of rectangle }=\text { length } * \text { width }

Substituting the values we get,

\begin{array}{l}{3197=(7 W-22)(W)} \n\n {3197=7 W^(2)-22 W} \n\n {7 W^(2)-22 W-3197=0}\end{array}

On solving the above quadratic equation using quadratic formula,

\text {For the quadratic equation } a x^(2)+b x+c=0 \text { where } a \neq 0

x=\frac{-b \pm \sqrt{\left(b^(2)-4 a c\right)}}{2 a}

\begin{array}{l}{\text {Here in } 7 \mathrm{W}^(2)-22 \mathrm{W}-3197=0} \n\n {a=7 ; b=-22 ; c=-3197}\end{array}

Substituting in above quadratic formula,

\begin{array}{l}{W=\frac{-(-22) \pm \sqrt{\left((-22)^(2)-4(7)(-3197)\right)}}{2 * 7}} \n\n {W=(22 \pm √(90000))/(14)=(22 \pm 300)/(14)} \n\n {W=(22+300)/(14) \text { or } W=(22-300)/(14)} \n\n {W=23 \text { or } W=-19.85}\end{array}

Since width of rectangle cannot be negative, ignore negative value of "W"

So width W = 23 inches

Length L = 7W - 22 = 7(23) - 22 = 139 inches

Thus length of rectangle is 139 inches

Twice the number of books divided by fifteen (Which represents the phrase?)

A. 2n/15
B. 15n/2
C. 2+n/15
D. n/2(15)

Answers

It is A. 2n/15. You can think of n as the books

Answer:

A

Step-by-step explanation:

2* the number of books is 2n then you have to divide by 2 so. . . 2n/15

A jacket is discounted 30% off. The original was $150.00. What is the new price of the jacket after the discount?

Answers

$105. 30% of 100 is 30 and 30% of 200 is 60 it'd be 45 off because it's the number between the 2. Leaving 150-45=$105
$50. So, first we have to take the original price and divide it. $150.00 divided by 3 equals $50.

How do I identify rational and irrational numbers?

Answers

Answer: An irrational number is a number that is NOT rational. It cannot be expressed as a fraction with integer values in the numerator and denominator. When an irrational number is expressed in decimal form, it goes on forever without repeating.

An irrational number can be written as a decimal, but not as a fraction. An rational number can be written as a ratio.

Find the points where the line y = x - 1 intersects the circle x2 + y2 = 13

Answers

Answer:

\large \boxed{(-2,-3) \text{ and } (3, 2)}

Step-by-step explanation:

1. Solve the equations for x

\begin{array}{lrcll}(1) & y & = & x - 1 & \n(2) & x^(2) + y^(2) &= &13& \n& x^(2) + (x - 1)^(2) &= & 13& \text{Substituted (1) into (2)}\n& x^(2) + x^(2) -2x +1 & = & 13 & \text{Squared (x - 1)} \n&2x^(2) -2x +1 & = & 13 & \text{Combined like terms} \n\end{array}\n

\begin{array}{lrcll}&2x^(2) -2x - 12 & = & 0 & \text{Subtracted 13 from each side}\n&x^(2) - x - 6 & = & 0 & \text{Divided each side by 2}\n& (x - 3)(x + 2) & = & 0 & \text{Factored the left-hand side} \n& x - 3 = 0 & \text{or} & x + 2 = 0 & \text{Applied zero product rule} \n& \mathbf{x = 3} & \text{or} & \mathbf{x = -2} & \text{Solved each equation separately} \n\end{array}

2. Calculate the corresponding values of y

Insert the values into equation (1)

(a) x = 3

y = 3 - 1 = 2

One point of intersection is (3, 2).

(b) x = -2

y = -2 - 1 = -3

The second point of intersection is (-2, -3).

\text{The line intersects the circle at $\large \boxed{\mathbf{(-2,-3)} \text{ and } \mathbf{(3, 2)}}$}

The diagram shows the intersection of the two graphs.

Answer:

(-2,-3) and (3,2)

Step-by-step explanation:

sub in x-1 into y

x^2 + (x-1)^2 = 13

x^2 + (x-1)(x-1)=13

x^2 + x^2 -2x +1 = 13

2x^2 -2x-12=0

solve for x by factoring (quadratic formula, product sum etc..)

x= -2 and 3

plug in those values into y=x-1 and solve for y

What are the 40th and 50th multiples of 15

Answers

40th multiples of 15 is 40 x 15 = 600

50th multiples of 15 is 50 x 15 = 750