An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respectively. A quantity of Cl2(g) is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of mixing). The system then re-equilibrates. The appropriate chemical equation is:PCl3(g) + Cl2(g) ---> PCl5(g)

Calculate the new partial pressures after equilibrium is reestablished. [in torr]

PPCl3

PPCl2

PPCl5

Answers

Answer 1

Answer:

equilibrium is a situation in which economic forces such as supply and demand are balanced and in the absence of external influences the values of economic variables will not change

The equilibrium constant depends on the following:-

Pressure
Volume

The formula used in the question is as follows:-

$k_p = (P_1)/(P_1*P_2)$ , After putting the value, the equilibrium constant is as follows:-

$k_p = (217)/(13.2*13.2)$

After solving it, the equilibrium constant is 1.245.

The pressure in different systems is as follows:-

Hence, the total pressure is:- $P_1 + P_2+ P_3$

$263 = 13.2 + P_2 + 217$

After solving it, the P2 is 32.8torr.

The equilibrium constant in the second case is:-

$k_p = (P_1^')/(P_1^' * P_2^')$

After putting the value,

$1.245= (217+x)/((13.2-x )* (32.8-x))$

After solving, the value of x is 6.402torr

Hence, the partial pressure $PCL_3,\ CL2, \ PLC_5\$ is 6.798, 26.398, and 223.402 respectively.

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Answer 2

Answer:

Answer:

The new partial pressures after equilibrium is reestablished for $PCl_3$ :

$P_1'=6.798 Torr$

The new partial pressures after equilibrium is reestablished $Cl_2$ :

$P_2'=26.398 Torr$

The new partial pressures after equilibrium is reestablished for $PCl_5$ :

$P_3'=223.402 Torr$

Explanation:

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At equilibrium before adding chlorine gas:

Partial pressure of the $PCl_3=P_1=13.2 Torr$

Partial pressure of the $Cl_2=P_2=13.2 Torr$

Partial pressure of the $PCl_5=P_3=217.0 Torr$

The expression of an equilibrium constant is given by :

$K_p=(P_1)/(P_1* P_2)$

$=(217.0 Torr)/(13.2 Torr* 13.2 Torr)=1.245$

At equilibrium after adding chlorine gas:

Partial pressure of the $PCl_3=P_1'=13.2 Torr$

Partial pressure of the $Cl_2=P_2'=?$

Partial pressure of the $PCl_5=P_3'=217.0 Torr$

Total pressure of the system = P = 263.0 Torr

$P=P_1'+P_2'+P_3'$

$263.0Torr=13.2 Torr+P_2'+217.0 Torr$

$P_2'=32.8 Torr$

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At initail

(13.2) Torr (32.8) Torr (13.2) Torr

At equilbriumm

(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr

$K_p=(P_3')/(P_1'* P_2')$

$1.245=((217.0+x))/((13.2-x)(32.8-x))$

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished for $PCl_3$ :

$P_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr$

The new partial pressures after equilibrium is reestablished $Cl_2$ :

$P_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr$

The new partial pressures after equilibrium is reestablished for $PCl_5$ :

$P_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr$

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B. positively charged.
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Answers

Answer:

The correct answer is option B. positively charged.

Explanation:

Hello!

Let's solve this!

When an atom yields its electrons, it yields part of its negative charge. Therefore, it immediately transforms into a positively charged ion.

This positively charged ion is called cation.

We conclude that the correct answer is option B. positively charged.

Positively charged due to donating two electrons and becoming an ion.

Please answer. Brainliest!

Answers

Answer:

The equation is balanced.

Explanation:

The number of P atoms in the reactant side is 4 and the number of P atoms in the product side is also 4.

The number of O atoms in the reactant side is 16 and the number of O atoms in the product side is also 16.

The number of H atoms in the reactant side is 12 and the number of H atoms in the product side is also 12.

These results are in accordance with the law of conservation of mass.

#ILoveChemistry

Do x-rays travel slower than infrared

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No, x-rays do not travel slower than infrared radiation or even the opposite. Both are travelling in vacuum therefore they travel at same speed. They differ in the frequency of the electromagnetic waves.

Which equation shows conservation of atoms?A) H2 + O 2 --> H2O
B) H2 + O 2 --> 2H2O
C) 2H2 + O2 --> 2H2O
D) 2H2 + 2O2 --> 2H2O

Answers

Answer: The equation showing conservation of atoms is $2H_2+O_2\rightarrow H_2O$

Explanation:

Every balanced chemical equation follows law of conservation of mass.

This law states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.

For the given chemical equations:

Option A:

The given chemical equation follows:

$H_2+O_2\rightarrow H_2O$

There are 2 hydrogen atoms and 2 oxygen atoms on the reactant side and 2 hydrogen and 1 oxygen atom on product side.

So, this equation does not show conservation of atoms.

Option B:

The given chemical equation follows:

$H_2+O_2\rightarrow 2H_2O$

There are 2 hydrogen atoms and 2 oxygen atoms on the reactant side and 4 hydrogen atoms and 2 oxygen atoms on product side.

So, this equation does not show conservation of atoms.

Option C:

The given chemical equation follows:

$2H_2+O_2\rightarrow H_2O$

There are 4 hydrogen atoms and 2 oxygen atoms on the reactant side and 4 hydrogen atoms and 2 oxygen atoms on product side.

So, this equation shows conservation of atoms.

Option D:

The given chemical equation follows:

$2H_2+2O_2\rightarrow 2H_2O$

There are 4 hydrogen atoms and 4 oxygen atoms on the reactant side and 4 hydrogen atoms and 2 oxygen atoms on product side.

So, this equation does not show conservation of atoms.

Hence, the equation showing conservation of atoms is $2H_2+O_2\rightarrow H_2O$

You may recall that the products of the complete combustion of ahydrocarbon are water vapor and carbon dioxide gas. Write the balanced
equation showing the combustion of methane. Do not forget to include the
states of matter of the reactants and the products. Hint: Methane is a gas at
standard temperature and pressure.

Answers

Answer: $CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)$

Explanation: According to law of conservation of mass, mass can neither be created nor be destroyed.

Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

This is an example of combustion reaction in which hydrocarbon reacts with oxygen to form carbon dioxide and water. This is an exothermic reaction in which a large amount of heat is liberated, thus water also exists as vapors.

$CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)$

CH4 + 2O2 --> CO2 + 2H2O

SOMEONE HELP PLEASEData:

Record the results of each of your physical property tests in the table below.

Wood Clay Brick Iron Aluminum Copper Nickel

Flexibility

(?/10)

Magnetism

(number of paper clips)

Thermal Conductivity

(W/(m·K))

Electrical Conductivity

(x107 S/m)

Mass (g) 10g 10g 10g 10g 10g 10g

Volume (cm3)

Formula:

L x W x H

Density

(g/cm3)

Formula:

D=M/V

Answers

The exercise is to measure and record the Physical properties of materials, such as flexibility, magnetism, thermal conductivity, electrical conductivity and density. Magnetism and flexibility can be observed directly, while density, thermal conductivity, and electrical conductivity require calculations.

The student is asked to measure and record the physical properties of various materials.

Flexibility can be rated subjectively on a scale of 1-10, with 10 being most flexible.

Magnetism can be tested by seeing how many paper clips each material can hold.

Thermal Conductivity (W/(m·K)) is a measure of a material's ability to conduct heat, while Electrical Conductivity (x107 S/m) measures the material's ability to conduct electricity.

For density, you need the mass (M) and volume (V) of the material.

The mass is given as 10g for all materials. You have to measure the volume (V) using the formula length x width x height (L x W x H).

Then plug M and V into the density formula D=M/V to get the density in g/cm3. Keep in mind that each material will have different properties.

Learn more about Physical properties of materials here:

brainly.com/question/34913809

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