A sample of sodium reacts completely with 0.213 kgkg of chlorine, forming 351 gg of sodium chloride. What mass of sodium reacted?

Answers

Answer 1
Answer:

Answer:

The mass of sodium reacted is 138 grams

Explanation:

Firstly, the chemical reaction should be represented with a balance chemical equation. The chemical equation can be written as follows.

Na = sodium

Cl2 = chlorine gas

Na + Cl2 → NaCl

The balanced equation is

2Na(s) + Cl2(g) → 2NaCl(aq)

Atomic mass of sodium = 23 grams per mol

Atomic mass of chlorine = 35.5 grams per mol

From the chemical equation the molar mass are as follows

Sodium = 2 × 23 = 46 grams

Chlorine = 35.5 × 2 = 71 grams

Sodium chloride =  2 × 23 + 2 × 35.5 = 117 grams

if 46 grams sodium reacted to produce 117 grams of sodium chloride

? grams of sodium react to produce 351 grams sodium chloride

grams of sodium reacted = (351 × 46)/117

grams of sodium reacted = 16146/117

grams of sodium reacted = 138  grams

Answer 2
Answer:

Answer:

0.138 kg of Na.

Explanation:

Equation of the reaction

2Na(aq) + Cl2(g) --> 2NaCl(s)

By stoichiometry, since 2 moles of Na reacted with 1 mole of Cl2 to produce 2 moles of NaCl. Therefore,

Calculating the number of moles present,

Cl2:

Number of moles = mass/molar mass

Molar mass of Cl2 = 35.5 * 2

= 71 g/mol.

= 213 * 71

= 3 moles.

NaCl:

Molar mass = 23 + 35.5

= 58.5 g/mol.

Number of moles = mass/molar mass

= 351/58.5

= 6 moles.

Since they both have equal moles,

Mass of Na = number of moles * molar mass

Molar mass of Na = 23 g/mol

= 23 * 6 moles

= 138 g

= 0.138 kg of Na.


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Elements in Group 17 form which ion?
A. 1
B. +1
C. -1
D. 0

Answers

Answer:

Elements in group 17 form C. -1 ions

It would b C. -1
hope this helps

What's the size of a astatine Atom compared to a tellurium Atom

Answers

In the periodic table, the group number of astatine is 17 while that of tellurium is 16, hence the size of astatine is larger as compared to tellurium as it has one more shell present in it's atom.

What is periodic table?

Periodic table is a tabular arrangement of elements in the form of a table. In the periodic table, elements are arranged according to the modern periodic law which states that the properties of elements are a periodic function of their atomic numbers.

It is called as periodic because properties repeat after regular intervals of atomic numbers . It is a tabular arrangement consisting of seven horizontal rows called periods and eighteen vertical columns called groups.

Elements present in the same group have same number of valence electrons and hence have similar properties while elements present in the same period show gradual variation in properties due to addition of one electron for each successive element in a period.

Learn more about periodic table,here:

brainly.com/question/11155928

#SPJ2

                         the answer is Astatine is one period further than tellurium, meaning it has an extra shell. Therefore, the At atom will be bigger than the Te atom.

Consider the reaction: K2S(aq)+Co(NO3)2(aq)=2KNO3(aq)+CoS(s) what volume of 0.255 M K2S solution is required to completely react with 160 mL of 0.130 M Co(NO3)2?

Answers

The volume will be "81.6 mL".

The given reaction is:

  • K_2S(aq)+Co(NO_3)_2(aq) \rightarrow 2KNO_3(aq)+CoS(s)

The values are:

Molarity of K_2S,

  • M_1 = 0.215 M

Volume of Co(NO_3)_2,

  • V_2 = 160 \ mL

Molarity of C0(NO_3)_2,

  • M_2 = 0.130 \ M

As we know,

V_1 = (M_2 V_2)/(M_1)

By substituting the values, we get

       = (0.130* 160)/(0.255)

       = (20.8)/(0.255)

       = 81.6 \ mL

Learn more:

brainly.com/question/3583591

based off of the chemical equation given, you know that K₂S reacts with Co(NO₃)₂ in a 1 to 1 molar ratio.  That means that the number of moles of both reactants need to be equal for both of them to completely react with each other.  

You can find the number of moles of Co(NO₃)₂ by multiplying 0.130M by 0.160L to get 0.0208 moles of Co(NO₃)₂.  That means that you need to find a volume of 0.225M K₂S that contains 0.0208 moles of K₂S.  You can do this by dividing the 0.0208 by 0.255 to get 0.0816L of K₂S.  That means that you need 81.6mL of 0.255M K₂S to fully react with 160mL of 0.130M Co(NO₃)₂.

I hope this helps.  Let me know in the comments if anything is unclear.

When might a large volume of material have little mass

Answers

A large volume of material will have a small amount of mass when thematerial in question is gaseous or porous, and therefore has a lot ofspace within it despite taking up a large amount of space overall.

In which type of reaction do two or more substances combine to produce a single substance?(1) synthesis
(2) decomposition
(3) single replacement
(4) double replacement

Answers

The correct answer is option 1. Synthesis reaction is the chemical reaction which involves two or more substances combining to form a single substance. An example is burning magnesium. The balanced reaction is 2Mg + O2 = 2MgO.

The correct answer is (1) Synthesis

Explanation:

In chemistry, synthesis reaction occurs as two or more substance combine and form a single and complex product, due to this, synthesis reaction is also known as a direct combination, because different to decomposition or replacement reactions the final product includes the substances that were combined. For example, water (H2O) is formed through synthesis by mixing two atoms of hydrogen (H2) and one of Oxygen (H) which means the substances combined form a single substance. Thus, the type of reaction described is Synthesis reaction.

Stoichiometry! Please note:
- Use 6.022x1023 for avogadro’s number
- Ignore sig figs and do not round the final answer.
- Keep it to 1 decimal place.

Answers

Answer:

a) 13.2 moles 2H_(2)O

b) 79.33 grams of 2H_(2)O

Explanation:

First, we'll need to balance the equation

H_(2(g)) + O_(2(g))H_(2)O_((g))

There are 2 (O) on the left and only one on the right, so we'll add a 2 coefficient to the right.

H_(2(g)) + O_(2(g))2H_(2)O_((g))

Now there are 4 (H) on the right and only 2 on the left, so we'll add a 2 coefficient to the (H_(2)) on the left.

2H_(2(g)) + O_(2(g))2H_(2)O_((g))

The equation is now balanced.

a) This can be solved with a simple mole ratio.

4.6 moles O_(2) × (2 moles H_(2)O)/(1 mole O_(2)) = 13.2 moles 2H_(2)O

b) This problem is solved the same way!

2.2 moles H_(2) × (2 moles H_(2)O)/(2 moles H_(2)) = 2.2 moles 2H_(2)O

However, this problem wants the mass of 2H_(2)O, not the moles.

The molecular weight of 2H_(2)O is the weight of 4 (H) molecules and 2 (O) molecules (found on the periodic table). So,

4(1.008) + 2(15.999) = 36.03 g/mol

2.2 moles 2H_(2)O × (36.03 g)/(1 mol) = 79.33 grams of 2H_(2)O