MATHEMATICS MIDDLE SCHOOL

What is 62.4 as a fraction and simplified?

Answers

Answer 1

Answer:

Answer:

62 2/5

Step-by-step explanation:

62 is just the whole number and then you have 4 tenths, which is 4/10 which can be simplified to 2/5, so it's 62 2/5

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Subtract. –56 – (–27.07)A.–83.07B.–28.93C.28.93D.83.07

Which products result in a difference of squares or a perfect square trinomial? Check all that apply. (5x + 3)(5x – 3) (7x + 4)(7x + 4) (2x + 1)(x + 2) (4x – 6)(x + 8) (x – 9)(x – 9) (–3x – 6)(–3x + 6)

Answers

In this question, we have to find all the products which result in a difference of perfect squares .

The formula of the difference between squares is

$(a-b)(a+b) = a^2-b^2$

In the first option, we have

$(5x+3)(5x-3)$

Which is of the form of difference of two squares. And similarly , the last option is also in the form of difference of two squares .

And for perfect squares, we have same factor twice in b and e, so for that b and e are the correct options .

So out of the given options, correct options are a,b,e and f .

Answer:

ONE: A
TWO:B

FIVE: E
SIX: F

I asked this so many times and still no answer answer someone pleaseInstructions In this experiment, you will be using two coins as a simulation for a real-world compound event. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.

1 What is the theoretical probability that the family has two dogs or two cats? Describe how to use two coins to simulate which two pets the family has.

Flip both coins 50 times and record your data in a table like the one below. Result Frequency Heads,

Heads Heads, 9

Tails Tails,26

Heads Tails,26

Tails 15

Total 50
Based on your data, what is the experimental probability that the family has two dogs or two cats?
If the family has three pets, what is the theoretical probability that they have three dogs or three cats?

How could you change the simulation to generate data for three pets?

I just need the last questons answered thank you so much

Answers

In order for the simulation to generate data for three pets, you would need three coins.

Rope is 5 meters long. It is cut into 8 equal parts. How long are each piece?

Answers

Answer:

0.625m PLEASE GIVE BRAINLIEST

Step-by-step explanation:

5 ÷ 8 = 0.625

So.... each piece is 0.625m long.

.625

5 divided by 8 is .625

Define perpendicular bisector as much as you can plus give example about them

Answers

A perpendicular bisector of a line segment is a line segment perpendicular to and passing through the midpoint of (the figure below). The perpendicular bisector of a line segment can be constructed using a compass by drawing circles centered at and with radius and connecting their two intersections.

Which of the following algebraic expressions can be used to express the statement "one less than x squared?" A. 1 − x to the power of 2
B. x to the power of2 − 1
C. 1 − 2x
D. 2x − 1

Answers

B. $x^(2) - 1$

B!! D to the power of 2-1!
Have a nice day!!

Is 9 a solution to 3y<27

Answers

No, because if y is in fact 9 then the expression $3y<27$ evaluates to $27<27$ which is a false hence y cannot be 9 but rather $y\in(-\infty,9)$ .

Hope this helps.

Answer: No

Step 1: Rewrite the equation

3y<27

Step 2: Get y alone

To do this we need to divide both 3y and 27 by 3

3y<27

3y/3<27/3

y=9

Step 3: Substitution

We now know that y equals 9. Now let’s substitute this into the equation

3y<27

3(9)<27

27<27

Step 4: Determining the answer

Since 27 is not less than (27), 9 is not the solution for y. However, any number less than 9 would work for this equation

Hope this helps comment below for more questions :)

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