Answer:
the 2 numbers are 29 and 62
Arithmetic Sequence
The values of a and b is a = 2 and b=3
Step-by-step explanation:
Given the terms of the arithmetic sequence are
2 , a - b , 2a + b + 7, a - 3b
Let the common difference be D
Therefore,
The difference between the first two consecutive terms is
(a – b) – 2 = D ------------------------------( 1 )
The difference between the next two consecutive terms is
D = (2a + b+7) – ( a - b ) ---------------------(2 )
Equating equation 1 and equation 2
⇒ (a – b) -2 =(2a+b+7)-(a-b)
⇒ a – b – 2 = a + 2b +7
⇒ 3b = -9
⇒ b = -3
Similarly
The difference between the next two consecutive terms is
D = (a-3b)-(2a+b+7) ------- (3)
⇒ (a-3b)-(2a+b+7)=(2a+b+7)-(a-b)
⇒ a-3b)-(2a+b+7) -a - 4b -7 === a+2b+7
⇒ 2a = - ( 14 + 6b)
⇒ a = -( 7 + 3b)
⇒ a = - ( 7 – 3*3 )
Thus the value of a = 2
Hence , the values of a and b is a = 2 and b=3
To find the values of a and b in an arithmetic sequence, we can set up a system of equations using the given terms. Solving the system will give us the values of a and b.
Let's use the information given to find the values of a and b. We can set up a system of equations using the first four terms of the arithmetic sequence.
The first term is 2, so we know that: a-b = 2.
The second term is a-b, so we can write: a-b + d = 2a+b+7, where d represents the common difference.
The third term is 2a+b+7, so we have: a-b + 2d = 2a+b+7 + d.
The fourth term is a-3b, so we get: a-b + 3d = a-3b + 2d.
We can solve this system of equations to find the values of a and b.
After simplifying and solving the system, we find that a = 10 and b = 8.
#SPJ3
(2, -5)
(4, 2)
(2, -1)
Answer:
(2,-1)
Im right because I got it right on my math quiz
First you had to divide fifty-eight by the six.
You can also round up to the nearest tenths is 9.67=10.00.
Explanation: The answer should be have a remainder 4 it is.
Final answer:
Hope this helps!
And thank you for posting your question at here on brainly, and have a great day.
-Charlie
the answer would be
58÷ 6 = 9.66666666667
we can round it to 9.67
hope it's helpfull