Answer:
About 428 N
Step-by-step explanation:
Weight = 1,500 * 9.8 = 14,700 N
Density = Mass ÷ Volume
1,030 = 1,500 ÷ V
V = 1,500 ÷ 1,030 = 1.46 m^3.
Buoyant force = Density * g * V
Buoyant force = 1,000 * 9.8 * (1,500 ÷ 1,030)
Buoyant force = 9,800 * (1,500 ÷ 1,030) = 14,272 N.
Net force = 14,700 – [(9,800 * (1,500 ÷ 1,030)]
The upward normal force on a 1500 kg submerged hippo is approximately equal to its weight, calculated as its mass times the acceleration due to gravity (1500 kg × 9.81 m/s²), resulting in a force of 14715 N.
The question is asking about the upward normal force on a submerged hippo in a lake. To find this force, we must understand that the upward normal force that the ground (or in this case, the lake bed) exerts on the hippo is equal to the weight of the hippo, which is the product of the hippo's mass (m) and the acceleration due to gravity (g).
In equation form: Normal Force = m × g. Plugging in the values, we have a 1500 kg hippo and the acceleration due to gravity is approximately 9.81 m/s². Therefore, the upward normal force is:
Normal Force = 1500 kg × 9.81 m/s² = 14715 N.
This is the approximate value of the upward normal force exerted on the hippo standing on the bottom of the lake.
#SPJ3
Answer: She payed a total of $33.60
Answer:
20 ft.
Step-by-step explanation:
Cross multiply.
Solve for the variable.
Answer:
1- $309.23
2- $107.10
3- 596.25
4- $8.18
There
Step-by-step explanation:
mate if u don’t pay attention In class next time I’ll be in ur dreamszzzzzzz with so many homeworkkkkk
jmucnefuuj4fucj4ujjfi
goodluck
1) a^2- 9a + 14 = 0
Answer:
rise over run
Step-by-step explanation:
rise: 5
run: 6
5/6 i think