Answer:
x − 1 ≤ 9 or 2x ≥ 24
Step-by-step explanation:
B. (T) = 0.7c + 0.08(0.7c)
C. (T) = 0.7 (0.3c + 0.08c)
D. (T) = 0.7 (c – 0.08c)
The correct formula to calculate Janice's total cost of the uniform is (T) = 0.7c + 0.08(0.7c), as stated in choice B.
To calculate Janice's total cost of the uniform, we need to take into account the 30% discount and the 8% sales tax. The correct formula to calculate the total cost (T) is (T) = 0.7c + 0.08(0.7c), which corresponds to choice B.
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Answer:
2x^2+6x+10
Step-by-step explanation:
In the attached file
Answer:
hi
Step-by-step explanation:
i think question is not complete
would you check it out
Answer: It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.
Step-by-step explanation:
Let us consider the general linear equation
Y = MX + C
On a coordinate plane, a line goes through points (0, negative 1) and (2, 0).
Slope = ( 0 - -1)/( 2- 0) = 1/2
When x = 0, Y = -1
Substitutes both into general linear equation
-1 = 1/2(0) + C
C = -1
The equations for the coordinate is therefore
Y = 1/2X - 1
Let's check the equations one after the other
y = negative one-half x minus 1
Y = -1/2X - 1
y = negative one-half x + 1
Y = -1/2X + 1
y = one-half x minus 1
Y = 1/2X - 1
y = one-half x + 1
Y = 1/2X + 1
It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.
Jeremy's claim that if a linear function has the same steepness (slope) and the same y-intercept, it must be the same function is not correct. A counterexample is y = negative one-half x + 1, which has the same steepness and y-intercept but is a different function.
The line going through points (0, negative 1) and (2, 0) can be expressed in slope-intercept form (y = mx + b) where the slope m can be calculated as (y2-y1)/(x2-x1) and the y-intercept b is the y-value when x=0. For this line, we have m = (0 - (-1))/(2-0) = 1/2 and b = -1. Hence, the equation for this line is y = one-half x - 1.
However, we can prove Jeremy's claim wrong with a counterexample. Even if a function has the same slope and y-intercept, it doesn't necessarily mean they represent the same function. A counterexample is y = negative one-half x + 1. This line has the same steepness (slope -1/2) but a different direction (its slope is negative, unlike the other line), and the same y-intercept (y=1 when x=0) but it's not the same function.
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