Please explain this to me

Answers

Answer 1

Answer:

Answer:

X- axis is the line at the bottom of the graph and y-axis is the line on the side

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Solve the quadratic equation for x. What is one of the roots? (x + 6)^2 = 49

PLEASE HELP SOON. i have been stuck on this algebra 1 question for what feels like an eternity can someone please help and soon?

Answers

You are trying to find an x-value for which f(x) = g(x). At first your choice of x is arbitrary. In the given table, the first x-value tried was 0 (zero). For this value of x, f(x) does NOT equal g(x).

Next x was 1. f(x) and g(x) are even further apart here. So reject 1 and try 2 instead. Notice how f(x) and g(x) are closer together now than they were for x=1.

Note that for x=2.5, f(x) and g(x) are even closer together; ony 0.75 separates them.

Your turn. Try x=2.4, x=2.3, and so on. You may have to go in the other direction: Try x=2.6, x=2.7, and so on. If f(x) and g(x) are getting closer to one another, you're going in the right direction; if further apart, you're going in the wrong direction.

Have fun. This really is an interesting problem.

Factors of 7 please!!!!!

Answers

the factors of seven are 1 and 7

7 --> 7, 14, 21, 28, 35, . . .

How to find a percentage of a number

Example: 30% off of 120 dollars

Answers

Times a number by a percent. First turn 30% Ino .3 by putting the decimal point 2 times to the l .

each percent is basically a decimal in a different form. So 30% .3 (just move the decimal 2 times). Now multiply 120 by .3 and get 36. Just subtract 36 from 120 and get 84.

In the cafeteria there are 7 teachers 48 girls and 45 boys What is the probability that a person chosen at random from the cafeteria is a boy

Answers

total peoples = 7 + 48+ 45 = 100
probability of boys = number of boys / total people
45/100 = 9/20

7+48+45
48+45=93
so 93% chance of a boy getting chosen

Given the function h(x) = 3(2)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.Part A: Find the average rate of change of each section. (4 points)

Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)

(10 points)

Answers

Answer:

Part A) The average rate of change of section A is 6 and the average rate of change of section B is 24

Part B) The average rate of change of Section B is 4 times greater than the average rate of change of Section A. see the explanation

Step-by-step explanation:

Part A) Find the average rate of change of each section

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

$(f(b)-f(a))/(b-a)$

In this problem we have

Section A

$a=1$

$b=2$

$f(a)=f(1)=3(2)^1=6$

$f(b)=f(2)=3(2)^2=12$

Substitute

$(12-6)/(2-1)=6$

Section B

$a=3$

$b=4$

$f(a)=f(3)=3(2)^3=24$

$f(b)=f(4)=3(2)^4=48$

Substitute

$(48-24)/(4-3)=24$

Part B) How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other

Divide the average rate of change section B by the average rate of change of Section B

$(Section\ B)/(Section\ A)=(24)/(6)$