Yo sup??
we have to apply trigonometric ratios ie sine
sin63=IJ/HJ
IJ=HJ*sin63
=8.0
Hope this helps.
Answer:
The answer should be 8. Hope this help you out.
Answer:
GoG = X⁴ + 4X² + 6
B.increase; increase
C.decrease; increase
D.increase; decrease
Answer:
increase; increase
Step-by-step explanation:
B. P(A) • P(B)
C. P(A) + P(B)
D. P(A x B)
Answer: The correct option is (B) P(A) • P(B).
Step-by-step explanation: Given that the probability for success of an event is P(A) and the probability of success of a second event is P(B).
We are to find the probability of both events occurring, in that order.
We know that
if two events are independent of each other, then the probability of the intersection of the two events is given by the product of the probabilities of the events.
Here, the event that both events occur is given by (A ∩ B).
And, so the probability of both events occurring, in that order will be
Thus, the required probability is P(A) • P(B).
Option (B) is CORRECT.
Answer:
20 ways
Step-by-step explanation:
6C3 = 6!/(3! * (6-3)!)
= (6*5*4*3*2*1)/(3*2*1*(3)!)
= (6*5*4) / (3 * 2 * 1)
= (6*5*4)/6
= 5 *4
= 20 ways
The number of ways to pick 3 items not to take out of a total of 6 is 20.
To find the number of ways to pick 3 items not to take out of a total of 6, we can use the combination formula. The formula for combinations is given by C(n, r) = n! / (r!(n-r)!), where n is the total number of items and r is the number of items to be chosen. In this case, n = 6 and r = 3. Plugging in these values, we get:
C(6, 3) = 6! / (3!(6-3)!) = 6! / (3!3!) = (6 * 5 * 4) / (3 * 2 * 1) = 20.
So, there are 20 different ways to pick 3 items not to take out of a total of 6.
#SPJ11
If you stretch on the y-axis then you are increasing/decreasing values at a every x.
The new function is therefore:
Hope this helps.