MATHEMATICS HIGH SCHOOL

Help solving statistic children participating at a one week summer camp made five new friends on average during the first six days of camp. If each child made two more friends on the last day of camp, then how many friends on average did the children make during the one week summer camp

Answers

Answer 1

Answer:

Answer:

On average the children on the camp made 7 new friends in the week.

Step-by-step explanation:

Given:

Average number of new friends camp made in 6 days = 5

Number of new friends made on the last day = 2

We need to find the number of new friends on average did the children make during the one week summer camp.

Solution:

Now we can say that;

to find the number of new friends on average did the children make during the one week summer camp is equal to sum of Average number of new friends camp made in 6 days and Number of new friends made on the last day.

framing in equation form we get;

the number of new friends on average made in 1 week = $5+2 =7$

Hence On average the children on the camp made 7 new friends in the week.

Answer 2

Answer:

Final answer:

On average, each child made 30 friends in the first six days of camp and another 2 on the last day, totaling an average of 32 friends made during the one week summer camp.

Explanation:

The children participating at the summer camp made an average of five new friends each for the first six days. This means they made a total of 5 friends/day * 6 days = 30 friends on average in the first six days. On the last day of camp, each child made two more friends. So, for the week as a whole, each child made an average of 30 friends from the first six days + 2 friends from the last day = 32 friends on average during the week-long summer camp.

Learn more about average here:

brainly.com/question/34817150

#SPJ3

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12x+5y==13-24x-5y=-11

-2x+4y=32
-5x-10y=-20

12x+12y=36
-8x-8y=-8

solve and explain

Answers

12x+5y=13 is y=13/5-12/5x
-24y-5y=-11 is y=-11/-5+(24/-5)x

-2x+4y=32 is y=32/4+2/4x
-5x-10y=-20 is y= -20/-10+(5/-10)x

12x+12y=36 is y=36/12-12/12x
-8x-8y=-8 is y=-8/-8+(8/-8)x

1. 12x + 5y = 13
-24x - 5y = -11

First Add these equations to cancel out the y value so we can find the x value.
(12x + 5y = 13) + (-24x - 5y = -11)
= -12x + 0y = 2
Now we are left with the equation -12x = 2
Next divide both sides by -12 and x = -1/6
Now plug x into any of the original two equations to find the y-value.

12(-1/6) + 5y = 13
-2 + 5y = 13
5y = 15
y = 3

or
-24(-1/6) - 5y = -11
4 - 5y = -11
-5y = -15
y = 3

Sp, x = -1/6 and y = 3

2.-2x + 4y = 32
-5x - 10y = -20

First, lets simplify both of the equations.

(-2x + 4y = 32) / -2 = x - 2y = -16
(-5x - 10y = -20) / -5 = x + 2y = 4

Now we have the two equations:

x - 2y = -16
x + 2y = 4

Subtract the equations from each other to cancel out the 'x'.
(x - 2y = -16) - (x + 2y = 4)
= -4y = -20

-4y = -20
Divide by -4
y = 5

Now plug 5 in for y in the equations:

x - 2y = -16
x + 2y = 4

x - 10 = -16
x = -6

x + 10 = 4
x = -6

So , y = 5, and x = -6

3. 12x + 12y = 36
-8x - 8y = -8

Lets also simplify the equations.

(12x + 12y = 36) / 12 = x + y = 3
(-8x - 8y = -8) / -8 = x - y = 1

Right off the bat you can say that x = 2 and y = 1.

2 + 1 =3
2 - 1 = 1

But mathematically:

Subtract both equations

(x + y = 3) - (x - y = 1)
= 2y = 2

2y = 2
y = 1

x + 1 = 3
x = 2

x - 1 = 1
x = 2

So x = 2 and y = 1;

Find the greatest common factor of 15x 2 y 3 and -18x 3 yz.

Answers

Answer:

Greatest common factor of $15x^2y^3$ and $-18x^3yz$ is $3x^2y$

Step-by-step explanation:

Greatest common factor is the common factor for two or more numbers such that greatest common factor divides both the number.

We find Greatest common factor by

doing prime factorization and then

taking common factors from all the factors and

if they do not have nay term common then Greatest common factor is 1.

Given Numbers are $15x^2y^3$ and $-18x^3yz$

First we do prime factorization of $15x^2y^3$ .

15 can be written as product of prime 3 and 5, so

$15x^2y^3=3 * 5 * x* x * y * y * y$

and Similarly, $-18x^3yz$ can be written as,

$-18x^3yz=-3 * 3* 2 * x* x * x* y* z$

Thus, taking common from both the terms,we get,

Greatest common factor as $3x^2y$

Multiply the GCF of the numerical part 3 and the GCF of the variable part x^2y to get
3x^2y.

Help me please Algebra Two!!

Answers

Answer:

a. -2, even mult. and 1, odd mult.

b. $(x+2)^2(x-1)$

c. Odd degree of 3 or higher, likely higher due to the turns in the graph.

Step-by-step explanation:

A polynomial graph has several features we look for to determine the equations.

The zeros of the function are the x-intercepts. If the x-intercepts touch but do not cross then the intercepts have an even multiplicity like 2, 4, 6, etc. If the x-intercepts cross over then they have an odd multiplicity.

Degree is the exponent or multiplicity of each zero. Therefore if we know the multiplicity of each zero we can add them together to find or make an educated guess for the degree of the entire polynomial.

The shape of the graph tells us what type of polynomial. Odd degrees have a backwards S shape. Even degrees have a W shape. The shape can even tell us the if the equation has a positive or negative leading coefficient. Upside down W or an M shape is negative. While a sideways S shape is negative.

In this graph, there are two real zeros: -2,1

We can write them in intercept or factored form as (x-1) and (x+2).

Because the graph never crosses the x-axis at x=-2 the zero has an even multiplicity of at least 2. The opposite is true for x=1 because it crosses. Therefore it has an odd multiplicity of at least 1.

The graph is a sideways s shape and ends up so is positive.

This means the function has a degree of 3 or higher with the degree being odd.

2. A highway makes an angle of 6 with the horizontal. This angle is maintained for a horizontal distance of 5 miles. To the nearest hundredth of a mile, how high does the highway rise in this 5-mile section? Show the steps you use to find the distance.

Answers

given:
angle of 6 : i'm assuming this is 6 degrees.
distance of 5 miles.

tan(6) = rise/5 mi
rise = 5 mi * tan(6)
rise = 5 mi * 0.10510423526
rise = 0.52552117632

rise = 0.53 miles.

Let the function f(x) have the form f(x) = Acos(x + C). To produce a graph that matches the one shown below, what must the value of A be?

Answers

A general cosine function has the form:

f(x) = A*cos(c + x)

We want to find the value of A that matches the one in the image, and we will find that A = 3

Ok, a general cosine function is:

f(x) = A*cos(c + x)

Where A is the amplitude.

To find the amplitude of a cosine function, we just need to find half of the difference between the maximum and minimum value of the function:

By looking at the given graph, we can see that the maximum is y = 3, and the minimum is y = -3

Then the amplitude is:

A = (3 - (-3))/2 = 6/2 = 3

The correct option is B.

If you want to learn more, you can read:

brainly.com/question/19830127

Answer: It’s 4 they’re all wrong (pretty sure I have the same graph)

Step-by-step explanation:

Evaluate the function at the given value of the independent variable and simplify. h(x)=lx-18l ; h(20)