Answer:
Washing your hands properly.
iron? (8 points)
Answer:
first change cm to m and g to kg so you will find the volume first which is 0.02 by 0.03 by 0.02 your answer is 0.000012 m . using the formula density=mass/volume take 0.094/ 0.00012 then divide
(2) 35.0% (4) 60.0%
Answer:
The correct option is (2) 35.0%
Explanation:
If we want to calculate the percent composition by mass of nitrogen in NH4NO3 we first need to calculate the mass of nitrogen in one mole of NH4NO3.
Because of the molecular form of NH4NO3 (it has 2 ''N'') we know that one mole of NH4NO3 contains 2 moles of N.
The molar mass of N (nitrogen) is
This means that 1 mole of N contains 14.0067 grams of N.
Because we have 2 moles of N ⇒
We know that in 1 mole of NH4NO3 we have 2 moles of N(28.0134 g of N).
To calculate the percent composition by mass of nitrogen we need to divide the mass of nitrogen in one mole of NH4NO3 by the mass of one mole of NH4NO3 and then multiply it by 100.
We know that in 1 mole of NH4NO3 there are 80.0 g of NH4NO3 (Because of the molar mass data) ⇒
% ≅ 35.0%
We find that the percent composition by mass of nitrogen in NH4NO3 is 35.0%
We conclude that the correct option is (2) 35.0%
1.Under pressure, sedimentary rocks form from igneous rock.
2.Igneous rocks can weather, creating sediments that form sedimentary rocks.
3. During weathering, sedimentary rocks melt and form igneous rock.
4.Under pressure, igneous rock undergoes changes that form sedimentary rock.
Answer:
2. Igneous rocks can weather, creating sediments that form sedimentary rocks
Explanation:
Sedimentary rocks are formed from Igneous rocks when rocks are broken down by weathering.
Answer:
It is a hydrogen bond.
Which of the following is a correct equilibrium expression?
A.
`"K"_("eq") = (["KOH"]^4["O"_2]^3)/(["KO"_2]^4["H"_2"O"]^2)`
B.
`"K"_("eq") = (["H"_2"O"]^2)/(["O"_2]^3)`
C.
`"K"_("eq") = (["KO"_2]^4["H"_2"O"]^2)/(["KOH"]^4["O"_2]^3)`
D.
`"K"_("eq") = (["O"_2]^3)/(["H"_2"O"]^2)`
Answer:
Answer is option D
Explanation:
The explanation is embedded in the word document attached
Answer:
Keq= [KOH]^4 [O2]^3/[[KO2]^4
Explanation:
4KO2(s) + 2H2O(l) → 4KOH(s) + 3O2(g)
Looking at the equation, the correct equilibrium expression is shown in the answer. The equilibrium constant for a reaction is given by the active masses of species involved in the reaction. The relative molar coefficients of species are raised to the power of their molar concentrations to give the active mass of each specie. This active mass now goes into the equilibrium equation.
Water is not included in the equilibrium equation because, as a solvent, it is present in large excess.
a neutralization reaction
a reaction in which oxidation numbers change
a reaction in which no electrons are transferred.