Mike has a mass of 97 kg. He jumps out of a perfectly good airplane that is 2000 m above the ground. After he falls 1000 m, when his downward speed is 68 m/s, Mike opens his parachute. The positive y-direction is downward.(a) Calculate the average magnitude of the upward force of the air resistance on Mike during his initial descent.

(b) After Mike opens his parachute, he continues to descend, eventually reaching the ground with a speed of 4.0 m/s. Calculate the average upward force during this part of Mike's descent.

(c) At the same time Mike jumps out of the airplane, his wallet (mass of 0.3 kg) falls out of his pocket. Calculate the wallet's downward speed when it reaches the ground. For this calculation, assume that air resistance is negligible.

Answers

Answer 1

Answer:

Final answer:

The average magnitude of the upward force of air resistance on Mike during his initial descent is 0 N. The average upward force during the descent after Mike opens his parachute is 1.552 N. The downward speed of the wallet when it reaches the ground is 196.196 m/s.

Explanation:

(a) Average magnitude of the upward force of air resistance:

To find the average magnitude of the upward force of air resistance during Mike's initial descent, we need to calculate the net force acting on him. This can be done by subtracting his weight from the gravitational force:

Net force = gravitational force - weight

Gravitational force = mass * acceleration due to gravity = 97 kg * 9.8 m/s2 = 950.6 N

Weight = mass * acceleration due to gravity = 97 kg * 9.8 m/s2 = 950.6 N

Net force = 950.6 N - 950.6 N = 0 N

Since the net force is 0 N, the average magnitude of the upward force of air resistance is also 0 N.

(b) Average upward force after opening parachute:

When Mike opens his parachute, air resistance plays a significant role in slowing him down. The average upward force can be calculated using the equation:

Average upward force = mass * acceleration

Acceleration = (final speed - initial speed) / time

Time = distance / (final speed - initial speed)

Acceleration = (4.0 m/s - 68 m/s) / (1000 m / (4.0 m/s - 68 m/s)) = 0.016 m/s2

Average upward force = 97 kg * 0.016 m/s2 = 1.552 N

(c) Speed of the wallet:

Since the wallet has negligible air resistance, we can use the equation for freefall to calculate its speed:

Final speed = initial speed + acceleration * time

Acceleration = acceleration due to gravity = 9.8 m/s2

Time = sqrt(2 * height / acceleration) = sqrt(2 * 2000 m / 9.8 m/s2) = 20.02 s

Initial speed = 0 m/s

Final speed = 0 m/s + 9.8 m/s2 * 20.02 s = 196.196 m/s

Therefore, the downward speed of the wallet when it reaches the ground is 196.196 m/s.

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Answer 2

Answer:

Final answer:

The force of air resistance on Mike during his initial descent and after opening his parachute is approximately 950.6 N. Ignoring air resistance, his wallet will reach the ground at approximately 198 m/s.

Explanation:

The subject of this question is Physics, and it requires understanding of forces and kinematics to apply to the real world scenario of skydiving.

Part (a)

During the initial descent, Mike doesn't have a parachute open. So, the only forces at play initially are his weight and the force of air resistance. We know that he achieves a steady speed of 68 m/s, which means the forces are balanced (net force is zero). Since weight and air resistance counterbalance each other, we calculate the weight by multiplying mass (97 kg) by acceleration due to gravity (9.8 m/s2), which yields 950.6 N. Given the forces balance, this is also the force of air resistance and the answer to part (a).

Part (b)

After the parachute opens, Mike continues to descend, eventually reaching the ground with a speed of 4.0 m/s, indicating a different balance between weight and airresistance. The weight remains the same, but the air resistance (upward force) has increased and once again equals weight since there is no acceleration. Hence, the upward force is still 950.6 N.

Part (c)

For the wallet, we're told to ignore air resistance. So, it's a free fall scenario. We can use the equation of motion v2 = u2 + 2gs to calculate the final speed. Initial speed (u) is 0, g is 9.8 m/s2 and s (displacement) is 2000 m. Substituting these values in, we calculate a final speed of approximately 198 m/s.

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A driver in a Volkswagen bug (mass = 1335 kg) pulls out going 10 miles per hour in front of a Ford pickup truck (mass = 2675 kg) which is traveling 40 miles per hour. The two vehicles experience a head-on collision. Which of the following statements is true concerning the forces that each vehicle (and driver) experience in this collision? a. The Volkswagen bug experiences a much greater force than the Ford pickup truck due to the greater speed of the truck.
b. The Volkswagen bug experiences a much greater force than the Ford pickup truck due to the larger mass of the truck.
c. The Volkswagen bug experiences a force that is the same as the Ford pickup truck experiences.
d. The Volkswagen bug experiences a much smaller force than the Ford pickup truck due to the smaller speed of the Volkswagen bug.
e. The Volkswagen bug experiences a much smaller force than the Ford pickup truck due to the smaller mass of the Volkswagen bug

Answers

Answer:C

Explanation:

Given

mass of Volkswagen $m_1=1335 kg$

speed of Volkswagen $v_1=10 mi/hr$

mass of Ford pick up $m_2=2675 kg$

speed of ford pick up $v_2=40 mi/hr$

When two bodies collide head-on then force experienced by both the bodies will be the same but opposite in direction.

According to newton's third law, the force exerted by one particle on another is equal to the force exerted by the second particle on first.

Thus two bodies will experience the same force

Answer:

c. The Volkswagen bug experiences a force that is the same as the Ford pickup truck experiences.

Explanation:

Given:

mass of Volkswagen bug, $m_v=1335\ kg$

speed of Volkswagen bug, $v_v=10\ mi.hr^(-1)$

mass of Ford pickup, $m_f=2675\ kg$

speed of Ford pickup, $v_f=40\ mi.hr^(-1)$

Since both undergo a head-on collision they both face the equal impact in accordance with the Newton's third law of motion which states that every action has equal and opposite reaction.

So the bug the force applied by the bug on the pickup is equal to the force applied by the pickup on the bug. This happens only till both the masses are in contact with each other.

Which relationship does Einstein's equation E = mc2 describe?. A.Energy can be converted to moles of atoms.. .
B.Energy is stronger than mass.. .
C.Mass can be converted to energy.. .
D.Mass is weaker than energy.

Answers

The relationship that Albert Einstein's equation E=mc2 describes is mass can be converted into energy. This makes the correct answer D.

I think it is C. E=mc2 is an equation that is meant to see how much energy is in mass.

what are some sources of error that could explain differences between your prediction and what you measured experimentally for sound speed

Answers

There are several potential sources of error that could explain differences between a predicted sound speed and the experimentally measured value. Some common sources of error include:

1. Instrumental Errors: Inaccuracies or limitations in the measurement instruments used to determine the sound speed. This could include issues with the calibration of the instruments, sensitivity limitations, or errors in reading the measurements.

2. Environmental Factors: Variations in temperature, humidity, and atmospheric conditions can affect the speed of sound. If these factors are not accounted for or if they fluctuate during the experiment, they can introduce errors in the measured value.

3. Experimental Setup: Mistakes or inaccuracies in the experimental setup can lead to discrepancies between predicted and measured values. This could involve errors in the positioning of the sound source and receiver, incorrect timing measurements, or improper alignment of the equipment.

4. Assumptions and Models: Simplifications or assumptions made in the theoretical prediction of sound speed can introduce errors. If the underlying physics or properties of the medium are not accurately accounted for, the predicted value may deviate from the experimental measurement.

5. Human Error: Errors or biases introduced by the experimenter during the measurement process, such as misinterpretation of data, incorrect calculations, or systematic errors in data collection or analysis.

It is important to identify and minimize these sources of error through careful experimental design, calibration, and repeated measurements. Additionally, conducting experiments in controlled conditions and using precise measurement techniques can help reduce uncertainties and improve the accuracy of the measured sound speed.

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An electron is pushed into an electric field from infinity where it acquires a 1-V electrical potential. Suppose instead that two electrons are pushed from infinity the same distance into the same electric field. The electrical potential of the two electrons is ___________.a) 0.5V
b) 1V
c) 0.25V
d) 4V
e) 2V

Answers

Answer:

The electrical potential of the two electrons is 1 V.

(b) is correct option.

Explanation:

Given that.

Electric potential = 1 V

We know that,

The electric potential depends on the distance.

The electric potential does not depend on the charge.

The formula of electric potential

$V=Ed$

Where, E = electric field

d = distance

Hence, The electrical potential of the two electrons is 1 V.

A strand of 10 lights is plugged into an outlet. How can you determine if the lights are connected in series or parallel?A) Unscrew one light. If the other lights stay on, it's a series circuit.
B) Unplug the strand. If the first light stays on, it's a series circuit.
C) Unscrew one light. If the other lights turn off, it's a series circuit.
D) Cut the strand in half. If the plugged in half stays on, it's a series circuit.

Answers

series circuits, the current runs through all of them and they are conncted by the bulbs, so if you unscrew one, all light turn off

paralell, they are kinda independent, if you unscrew one, nothing happens to others

look at options
A. unscrew 1 light, if stay on, it's series, false, that's paralell

B. unplug, if stay on (then you have pozessed lights)

C. unsrew light, if stays on, it's parlell RIGHT ANSWER

D. cut strand in half (will cut power) if the plugged half stays on, then (pozessed circuit)

answer is C

A ball is dropped off a bridge and it takes 5 seconds to hit the water below. About how fast is the ball traveling just before it hits the water?

Answers

Explanation:distance between bridge and water as "x"meters

speed=distance * time

speed= x * 5

speed=5x m/s

Final answer:

The speed of a ball dropped off a bridge that takes 5 seconds to reach the ground is calculated using the equation of motion v = gt. With the acceleration due to gravity approximately 9.8 m/s², the ball would be traveling about 49 m/s just before it hits the water.

Explanation:

This question relates to the physics concept of gravity. When an object is dropped off with no initial velocity, the only force acting upon it is gravity. The speed of the falling object can be found using the equation of motion: v = gt, where g is the acceleration due to gravity (approx. 9.8 m/s²) and t is the time the object is in motion. Therefore, for a ball being dropped off a bridge for 5 seconds, the speed just before hitting the water would be approximately 49 m/s (9.8 m/s² * 5s).

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