Answer:
a) The probability is 0.04
b) The probability is 0.36
c) The pprobability is 0,25
d) The probability is 0.09
Step-by-step explanation:
Lets calculate areas:
the target has a radius of 10 inces, hence the target area has a area on 10²*π = 100π square inches.
a) A circle of 2 inches of radius has an area of 2²π = 4π square inches, hence the probability of hitting that area is 4π/100π = 1/25 = 0.04
b) If the dart s within 2 inches of the rim, then it is not at distance 8 inches from the center (that is the complementary event). The probability for the dart to be at 8 inches of the center is 8²π/100π = 64/100 = 16/25 = 0.64, thus, the probability that the dart is at distance 2 or less from the rim is 1-0.64 = 0.36.
c) The first quadrant has an area exactly 4 times smaller than the area of the target (each quadrant has equal area), thus the probability for the dart to fall there is 1/4 = 0.25
d) If the dart is within 2 inches from the rim (which has probability 0.36 as we previously computed), then it will be equally likely for the dart to be in either of the 4 quadrants (the area that is within 2 inches from the rim forms a ring and it has equal area restricted on each quadrant). Therefore, the probability for the dice to be in the first qudrant and within 2 inches from the rim is 0.36*1/4 = 0.09.
If you start with 1 cheerleader in row A, then you'll have 3 cheerleaders in row B (add on 2), and then 5 cheerleaders for row C (add on another 2), etc etc.
Note how: 1+3+5 = 4+5 = 9 which is a perfect square. Also note that 36 is a perfect square.
Rule: The sum of the first positive n odd numbers is going to be equal to n^2. In the example of adding the first three odd numbers (1,3,5), we have n^2 = 3^2 = 9 as the sum
So as you can see, we'll have n = 6 rows because n^2 = 6^2 = 36 and
1+3+5+7+9+11 = 36
which is the sum of the first six positive odd numbers. So we'll have 1 cheerleader in row A, 3 in row B, 5 in row C, 7 in row D, 9 in row E, 11 in row F to have 6 rows total.
To determine the number of rows in the triangular formation, set up an equation and solve for x. The number of rows is 6.
To determine the number of rows in the triangular formation, we can set up a series of equations.
Let x be the number of rows.
The first row will have 1 cheerleader, the second row will have 3 cheerleaders, the third row will have 5 cheerleaders, and so on.
We can set up the equation: 1 + 3 + 5 + ... + (2x-1) = 36.
This is the sum of an arithmetic sequence with a common difference of 2. Solving for x, we get x = 6.
Therefore, there will be 6 rows in the formation.
#SPJ12
decrease your scale values
B.
increase your scale values
C.
plot more points
D.
plot fewer points
Answer:
Option: B is correct.
B) Increase your scale values.
Step-by-step explanation:
When creating a scatterplot, if the points are too close together to see the relationship,then we must increase the scale value of our graph .
" Because by doing so the point will seem to be farther and we could see the clear relationship between the points and hence it will not create any confusion regarding the visual of the points and hence easily the inference could be drawn"
Hence, option: B is true.
(B) Increase the scale value)
Answer: The answer is 15.
Step-by-step explanation: Given that there are a total of 60 students who signed up for hockey, where there were 3 boys for every 1 girl who signed up. We are to find the number of girls who signed up.
The ratio of the number of boys to the number of girls will be 3 : 1.
Let '3x' and 'x' be the number of boys and number of girls respectively who signed up.
Therefore, we have
Thus, the number of girls is 15.
ATQ
Answer:
let Oscar's years be x
• Oscar → x
• Lois → (x+3)
B) 200 cm ^2
C) 25 cm ^2
D) 100 cm ^2