Answer:
Answer:
12
Explanation:
find the median:
19
find median of 10, 11, 12, 15, 17
median: 12
Answer:
The best description would be a bush.
Explanation:
Evolution resembled a tree, with a trunk branching off into different branches, which branch off into smaller branches, etc. This is basically the same as a bush. Any kind of line that's just a line, without any branching out, doesn't properly represent evolution because it only follows one line of evolution instead of accounting for the full picture.
which ones are acids and which ones are bases
Answer:
Explanation:
The chemical equation is:
There are several definitions of acid and bases: Arrhenius', Bronsted-Lowry's and Lewis'.
Bronsted-Lowry model defines and acid as a donor of protons, H⁺.
In the given equation HNO₃ is such substance: it releases an donates its hdyrogen to form the H₃O⁺ ion.
On the other hand, a base is a substance that accepts protons.
In the reaction shown, H₂O accepts the proton from HNO₃ to form H₃O⁺.
Thus, H₂O is a base.
In turn, on the reactant sides the substances can be classified as acids or bases.
H₃O⁺ contain an hydrogen that can be donated and form H₂O; thus, it is an acid (the conjugated acid), and NO₃⁻ can accept a proton to form HNO₃; thus it is a base (the conjugated base).
The equation is not balanced because the number of atoms of Oxygen present in the reactants and product sides are not equal
The equation being referred to in the question can be written properly as
S + 3O₂ → SO₃
To determine whether the equation is balanced or not
We will check if the coefficient in the equation gives equal numbers of atoms for each element in the reactants and product
S = 1
O = 6
S = 1
O = 3
We can observe that, the coefficient does not give equal number of atoms for the element, Oxygen (O), in the reactants and product sides
∴ The equation is NOT balanced
Hence, the equation is not balanced because the number of atoms of Oxygen present in the reactants and product sides are not equal
Learn more here: brainly.com/question/24943155
Answer:
This equation is not balanced because you don't have the same amount of each element on each side of the chemical reaction. The balanced equation is:
2 S + 3 ⇒ 2
Explanation:
The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.
Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts.
The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.
By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.
Then, taking into account all of the above, you can determine the amount of elements on each side of the equation:
Left side: 1 sulfur S and 6 oxygen O (coefficient 3 multiplied by sub-index 2)
Right side: 1 sulfur S and 3 oxygen O (subindice value)
As you can see, you have the same amount of sulfur on both sides of the equation but the amount of oxygen is different. This indicates that the chemical equation is not balanced. To balance it, as the amount of sulfur is the same, the amount of oxygen must be balanced, which is different on each side of the reaction.
A simple way is to balance the equation is to multiply the product by 2, that is, add a coefficient 2 in front of the SO3 molecule, the reaction being as follows:
S + 3 ⇒ 2
Now the amount of elements on each side of the equation is:
Left side: 1 sulfur S and 6 oxygen O (coefficient 3 multiplied by subindice 2)
Right side: 2 sulfur S and 6 oxygen O (coefficient 2 multiplied by subindice 3)
The oxygen is now balanced, but the amount of sulfur on both sides of the reaction varies. To balance the quantities of sulfur, as now on the right side you have an amount of 2, you can add the coefficient to sulfur. The chemical equation is as follows:
2 S + 3 ⇒ 2
Now the amount of elements on each side of the equation is:
Left side: 2 sulfur S and 6 oxygen O (coefficient 3 multiplied by subindice 2)
Right side: 2 sulfur S and 6 oxygen O (coefficient 2 multiplied by subindice 3)
Finally you have the same amount of sulfur and oxygen on both sides of the reaction. So the chemical equation is finally balanced.