The molarity of the NaOCl solution is 0.10M
The correct answer to the question is Option C. 0.10 M
We'll begin by calculating the number of mole of NaOCl required to produce 0.010 mole of Cl₂.This can be obtained as follow:
NaOCl + 2HCl —> Cl₂ + NaCl + H₂O
From the balanced equation above,
1 mole of NaOCl reacted to produce 1 mole of Cl₂.
Therefore
0.010 mole of NaOCl will also react to produce 0.010 mole of Cl₂.
Mole of NaOCl = 0.01 mole
Volume = 100 mL = 100 / 1000 = 0.1 L
Molarity = mole / Volume
Molarity of NaOCl = 0.01 / 0.1
Therefore, the molarity of the NaOCl solution is 0.1 M
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Answer:
Option C 0.10 M
Explanation:
you are not providing the reaction, but luckily we have data to write the equation. We know that we are taking HCl and NaOCl to produce Cl2, the reaction is as follow:
NaOCl + 2HCl ---------> Cl₂ + NaCl + H₂O
From this reaction, we know that we have excess of acid that is added to 100 mL (0.1 L) of NaOCl, and this produces 0.010 moles of Chlorine.
All we have to do here, is apply stechiometry. We already know that the acid is in excess, so the moles produced would be the moles of the limiting reactant, in this case, the NaOCl.
According to the reaction NaOCl and Cl2 has a mole ratio of 1:1, so the moles of Cl2 would be the same moles that NaOCl lost so:
moles Cl2 = moles NaOCl = 0.010 moles
Then the concentration:
M = 0.010 / 0.1
M = 0.10 M
This is the molarity of NaOCl
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Cf, the element has the following mass spectrum. Therefore, option (D) is correct.
California (Cf) is a radioactive element with a complicated mass spectrum that shows its isotopic makeup and decay trends. Peaks in Cf's mass spectrum denote isotopes with differing mass-to-charge ratios. These peaks signify isotopes, which are elemental atoms with varying neutron counts.
The mass spectrum yields important information about the sample's isotope abundance and masses. Researchers can determine Cf's isotopic distribution and nuclear characteristics like decay modes and half-lives by analyzing peaks and intensities. This is crucial since Cf's radioactivity and prospective uses in nuclear research and medicine are vital.
In conclusion, Californium's massspectrum reveals its isotopic makeup and behavior, helping researchers understand its characteristics and uses. Therefore, option (D) is correct.
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the answer is cf that the answer
phase change
physical change
nuclear change
Considering the reaction stoichiometry, 22.2 moles of Fe(OH)₂ are required to produce 7.4 moles of Fe₃(PO₄)₂.
The balanced reaction is:
3 Fe(OH)₂ + 2 H₃PO₄ → Fe₃(PO₄)₂ + 6 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Then you can apply the following rule of three: if by reaction stoichiometry 1 mole of Fe₃(PO₄)₂ requires 3 moles of Fe(OH)₂, 7.4 moles of Fe₃(PO₄)₂ require how many moles of Fe(OH)₂?
amount of moles of Fe(OH)₂= 22.2 moles
Finally, 22.2 moles of Fe(OH)₂ are required to produce 7.4 moles of Fe₃(PO₄)₂.
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Answer:
22.2 mol
Explanation:
A. 13.4
B. 0.0134
C. 0.00000134
Answer:
ACETYL-CoA, FADH
2 NADH
acetyl-CoA
Explanation: Beta oxidation of carbons of fatty acid acid molecules leads to the formation Acetyl-CoA, FADH and NADH.
The overall reaction for the process
Cn-acyl-CoA + FAD + NAD+
+ H
2O + CoA → Cn-2-acyl-CoA + FADH
2 + NADH + H+
+ acetyl-CoA.
formula of NADH is C21H27N7O14P2
formula of FADH is C27H35N9O15P2.
Both NADH(Nicotinamide adenine dinucleotide) and FADH( Flavin adenine dinucleotide) are
formular for Acetyl CoA IS C23H38N7O17P3S.
Beta oxidation is a breakdown process taking place in living systems which catabolises the fatty acids through glycolysis or fermentation leading to the release of Acetyl CoA, NADH AND FADH2.