A package of aluminum foil is 63.2 yd long, 11 in. wide, and 0.00035 in. thick. If aluminum has a density of 2.70 g/cm³, what is the mass, in grams, of the foil?
Answers
Answer:
Mass of aluminium foil = 387.57_g
Explanation:
density of aluminium foil 2.70 g/cm³,
1_yd = 91.44_cm
1_in = 2.54_cm
Length of aluminum foil = 63.2_yd = 5779.008_cm
Width of aluminium foil = 11 in = 27.94_cm
Thickness of aluminium foil = 0.00035_in. = 0.000889_cm
Volume of aluminium foil = length × width × thickness = 5779.008_cm × 27.94_cm × 0.000889_cm = 143.54_cm^3
Mass of aluminium foil = (volume of aluminium foil) × (density of aluminium foil) = 143.54_cm³ × 2.70 g/cm³ = 387.57_g
Final answer:
To find the mass of the aluminium foil, calculate the volume and multiply it by the density. The mass of the foil is 0.3878 grams.
Explanation:
To find the mass of the aluminium foil, we need to calculate the volume and then multiply it by the density. First, let's convert the dimensions to the same unit. The aluminium foil is 63.2 yd long, which is equivalent to 190.4 ft. The width is 11 in, which is 0.92 ft, and the thickness is 0.00035 in, which is 2.92e-5 ft.
The volume of the foil can be calculated by multiplying the length, width, and thickness.
V = (190.4 ft) * (0.92 ft) * (2.92e-5 ft).
This gives us a volume of 5.0634e-3 cubic feet.
Next, we need to convert the volume to cubic centimetres because the density is given in g/cm³.
There are 28.3168 cubic centimetres in one cubic foot, so the volume in cm³ is
5.0634e-3 * 28.3168 = 0.1433 cm³.
Finally, we can calculate the mass by multiplying the volume by the density.
Mass = 0.1433 cm³ * 2.70 g/cm³ = 0.3878 grams.
So, The mass of the foil is 0.3878 grams.
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Answers
Answer: Option (B) is the correct answer.
Explanation:
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For example, shows that HBr is an Arrhenius acid.
Whereas Arrhenius bases are the substances that produce hydroxide ions when dissolved in a solution.
For example, shows that KOH is an Arrhenius base.
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Answers
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B.4
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the answer is a
Answers
Answer:
Its a
Explanation:
I got that answer on my own not from the Question ;)
Final answer:
The third energy level in an atom, as described by quantum mechanics, contains three sublevels: the s, p, and d sublevels.
Explanation:
In the field of chemistry, the term energy level refers to the fixed amount of energy that a system described by quantum mechanics, such as a molecule, atom, electron, or nucleus, can have. Specifically, when we refer to the third energy level, we're talking about an energy state with the principal quantum number n=3.
For any energy level defined by the principal quantum number n, there are n sublevels. Therefore, in a third energy level (n=3), we have three sublevels. These would be the s, p, and d sublevels.
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