What is the product (3x-6)(2x2-7x+1)

Answers

Answer 1

Answer:

Answer:

$\large\boxed{6x^3-33x^2+45x-6}$

Step-by-step explanation:

$\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\n\n(3x-6)(2x^2-7x+1)\n\n=(3x)(2x^2)+(3x)(-7x)+(3x)(1)+(-6)(2x^2)+(-6)(-7x)+(-6)(1)\n\n=6x^3-21x^2+3x-12x^2+42x-6\qquad\text{combine like terms}\n\n=6x^3+(-21x^2-12x^2)+(3x+42x)-6\n\n=6x^3-33x^2+45x-6$

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Find an explicit formula for the arithmetic sequence -45,-30,-15,0...

Answers

Answer:

15(n-1)-45

Step-by-step explanation:

Increases by 15, so sequence is arithmetic, and goes to positive.

1st term is -45

so 15(n-1) gives us first term.

Reply for any questions I got you

$\bf -45~~,~~\stackrel{-45+15}{-30}~~,~~\stackrel{-30+15}{-15}~~,~~\stackrel{-15+15}{0}~\hspace{7em}\stackrel{\textit{common difference}}{d=15} \n\n[-0.35em] ~\dotfill\n\n n^(th)\textit{ term of an arithmetic sequence} \n\n a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^(th)\ term\n n=\textit{term position}\n a_1=\textit{first term}\n d=\textit{common difference}\n \cline{1-1} a_1=-45\n d=15 \end{cases} \n\n\n a_n=-45+(n-1)15\implies a_n=-45+15n-15\implies a_n=15n-60$

I need a real answer fast thank you

Answers

12.2 I believe but I'm not sure

2-2s=3/5s+13
Solve for s

Answers

Hello!

$S=-55/13$

Simplify both sides of the equation

$2-2s=3/5s+13$

$2+-2s=3/5s+13$

$-2s+2=3/5s+13$

Subtract 3/5s from both sides

$-2s+2-3/5s=3/5s+13-3/5s$

$-13/5s+2=13$

Subtract 2 from both sides

$-13/5s+2-2=13-2$

$-13/5s=11$

Multiply both sides by 5/(-13)

$(5/-13)*(-13/5s)=(5/-13)*11$

Answer:

s=-55/13

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2−2s=35s+13

2+−2s=35s+13

−2s+2=35s+13

Step 2: Subtract 3/5s from both sides.

−2s+2−35s=35s+13−35s

−135s+2=13

Step 3: Subtract 2 from both sides.

−135s+2−2=13−2

−135s=11

Step 4: Multiply both sides by 5/(-13).

(5−13)*(−135s)=(5−13)*(11)

s=−55/13

What is equivalent to (9x^2y^3) (12x^-3y^5) ( 2xy)

Answers

(((9•(x2))•(y3))•((22•3x(-3))•y5))•2xy((32x2 • y3) • (22•3x(-3)y5)) • 2xyMULTIPLYING EXPONENTIAL EQUATIONS:3.1    x(-1) multiplied by x1 = x((-1) + 1) = x0 = 1 Any number to the zero power is 1
MULTIPLYING EXPONENTIAL EQUATIONS:3.2    y8 multiplied by y1 = y(8 + 1) = y9
MULTIPLYING EXPONENTS: 3.3    22 multiplied by  21   = 2(2 + 1) = 23
FINAL RESULT:(33•23y9)

At the county fair the Baxter family bought 6 hot dogs and 4 sodas for $15.10. The Farley family bought 3 hot dogs and 4 sodas for $10.15. If someone ordered tow hotdogs, how much would they pay in total

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