Answer:
137
Step-by-step explanation:
Answer:
137
Step-by-step explanation:
17 + 20 + 50 + 50 = 137
Hope this helps
Both expressions should be evaluated with one value. If the final values of the expressions are both positive, then the two expressions must be equivalent.
Both expressions should be evaluated with one value. If the final values of the expressions are the same, then the two expressions must be equivalent.
Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are positive, then the two expressions must be equivalent.
Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.
Answer: Both expressions should be evaluated with one value. If the final values of the expressions are the same, then the two expressions must be equivalent.
Step-by-step explanation:
4x - x + 5 = 8 - 3x - 3
Combine like terms
4x - x + 5 = 5 - 3x
Subtract x from 4x
3x + 5 = 5 - 3x
Add -3x to both sides
6x + 5 = 5
Subtract 5 from each side
6x = 0
Divide by 6
x = 0
Put 0 into the equation
4(0) - 0 + 5 = 8 - 3(0) - 3
Multiply
0 - 0 + 5 = 8 - 0 - 3
Subtract
5 = 5
Answer:
B
Step-by-step explanation:
Answer:
x = 33/5
Step-by-step explanation:
x - 3/5 = n.......n = 6
so we sub
x - 3/5 = 6......add 3/5 to both sides
x = 6 + 3/5...convert using common denominator of 5
x = 30/5 + 3/5
x = 33/5 <===
check...
x - 3/5 = 6
33/5 - 3/5 = 6
30/5 = 6
6 = 6 (correct)...so it checks out
Fifth degree polynomial; scary stuff. We know it has five complex roots, counting multiplicities. How many are real?
The rational root test tells us we only have to try the divisors of 9, so 1, -1, 3, -3, 9, -9. We find x=3 gives
243 - 243 - 54 + 54 - 9 + 9 = 0
in nice pairs.
So x-3 is a factor and we can divide to get a 4th degree polynomial. The division is a bit easier than usual.
x^4 - 2x^2 - 3
x - 3 | x^5 - 3x^4 - 2x^3 + 6x^2 - 3x + 9
x^5 - 3x^4
0 - 2x^3 + 6x^2
0 - 3x + 9
0
So we get
It's downhill from here. The new factor is really just a quadratic in x squared, and factors easily:
And now if we descend into irrational and complex numbers, we can further factor
and we can read off our roots,
We have one rational root, namely 3, and two irrational roots, the square roots of three, and two purely imaginary roots.
Answer: 1 rational, 2 irrational
Answer:
One rational and 2 irrational zeroes
Step-by-step explanation:
I agree with the other guy.
f(3) = 0 so x = 3 is a rational root.
There also are 2 irrational roots and 2 complex roots.
.
.