A can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company'sclients needs a cylindrical can that has the same volume but is 15 cm tall. What must the new radius be to meet the
client's need? Round to the nearest tenth of a centimeter.
2.7 cm
4.9 cm
O 7.3 cm
24.0 cm
Answers
Answer:
Step-by-step explanation:
V=πr²h
=3.14*6*6*10
=1130.4 cm³
New cylinder:
h = 15cm
V= 1130.4 cm³
πr²h = 1130.4
3.14*r²*15=1130.4
r²=1130.4/15*3.14
r²=24
r=√24
r=4.898 = 4.9 cm
The radius be to meet the client's need is 4.9 cm.
What is Volume?
Volume is a mathematical term used to describe how much three-dimensional space an item or closed surface occupies.
Volume is sometimes referred to as capacity.
We have,
Radius of cylinder (r)= 6 cm
Height of cylinder (h) = 10 cm
and, Height of new cylinder (H) = 15 cm
Radius of new cylinder = R cm
Now, Volume of cylinder can be compared as
πr²h = πR²H
6 x 6 x 10 = R² x 15
360 / 15 = R²
R² = 24
R= 4.9 cm
Thys, the radius is 4.9 cm.
Learn more about Volume here:
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Answer:
132.56
Step-by-step explanation:
Answers
1.21 * 10-²
Answers
x = 2.16666666
10x = 21.6666666
100x = 216.666666
100x - 10x = 216.666666 (repeat) - 21.6666666 (repeat) = 195
90x = 195
x = 195 / 90
x = (195/3) / (90/3)
x = 65 / 30
x = (65/5) / (30/5)
x = 13 / 6
x = 13/6
Answers
Answers
Answer:
5/7
Step-by-step explanation:
Find the GCD of the numerator and denominator
GCD of 10 and 14 is 2
Divide both the numerator and denominator by the GCD
10 ÷ 2
14 ÷ 2
Reduced fraction:
5/7