Which of the following would indicate that a dataset is skewed to the right? a. The interquartile range is larger than the range.
b. The range is larger than the interquartile range.
c. The mean is much larger than the median.
d. The mean is much smaller than the median.

Answers

Answer 1
Answer:

Answer: c. The mean is much larger than the median

Step-by-step explanation:

A dataset is skewed to the right when the peak of the dataset is located in the left( left of the mean), and it has a long right tail. It is also call positive skewed distribution. One of the characteristics of right skewed dataset is that the mean of the dataset is always greater/larger than the median and mode.

Therefore, for the case above if the mean is much larger than the median, it indicates that the dataset is skewed to the right.

Answer 2
Answer:

A dataset is skewed to the right when the mean is much larger than the median. Therefore, the correct answer is option c.

When a dataset is skewed to the right, it means that the distribution of data is not symmetric, and it is stretched out more towards the higher values (right side) than the lower values (left side). This can be due to the presence of outliers or a natural characteristic of the data.

Now, let's look at why option "c" indicates right skewness:

c. The mean is much larger than the median.

The mean is the arithmetic average of all the values in the dataset, while the median is the middle value when the data is arranged in order. When a dataset is positively skewed (skewed to the right), it means that there are some significantly larger values in the right tail of the distribution that pull the mean to the right (towards higher values).

In this situation:

The mean gets pulled toward the larger values because the larger values have a greater impact on the mean due to their magnitude.

The median remains closer to the bulk of the data because it is not affected by extreme values as much as the mean.

So, when the mean is much larger than the median, it is an indication that there are significant outliers or a longer right tail in the dataset, which is a characteristic of a right-skewed distribution.

Therefore, the correct answer is option c.

Learn more about Skewed to the right here:

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What is 191x21=?????

Answers

191 times 21
191 times 21=191 times (20+1) correct?
therefor
use distributive property
remember that it is a(b+c)=ab+ac
therefor
191 times 21=191(20+1)=191 times 20+191 times 1=191 times 2 times 10+191=382 times 10+191=3820+191=4011
answer is 4011

191
×21
------
191
+382
---------
4011

answer= 4011
hope it helps

Mrs. Yamaguchi's class weighed the potatoes that they grew in their garden and recorded the data in a table. What are the least and greatest weights of the potatoes in the data set?

Answers

The least and greatest weights of the potatoes in the data set are 1/8 and 3/4 respectively.

How to find the least and greatest weight?

The weight of the potatoes are:

  • 1/4 = 0.25

  • 3/8 = 0.375

  • 5/8 = 0.625

  • 1/2 = 0.5

  • 3/4 = 0.75

  • 1/8 = 0.125

Therefore, the least weight of the potatoes is 1/8 equivalent to 0.125

The greatest weight of the potatoes is 3/4 equivalent to 0.75

Learn more about fractions:

brainly.com/question/1622425

Please help. Question is in the picture

Answers

Hey,here is the answer to ur question..!
1.BD=AE (given)
2. Ci Is the midpoint of BD and AE (given)
3. AC=EC (Cis the midpoint Of AE)
4. BC=DC (midpoint theorem)
5.angle ACB and angle ECD are vertical angles ( definition of vertical angles)
6. angle ACB=angle ECD (vertical angle theorem)
7.triangle ABC Is congruent to triangle EDC ( SSS criterion rule)
Hope this helps u....!!!

Using the breaking apart method, what is the best way to multiply 8 by 7?

Answers


ok 8 * 7 = 56 but your trying to break apart so ..

So ur trying to break apart 7 and 8 to still get ur sum 56 , so first , we are going to break up 8 which is 4 ... so we have 4 and 4 cause 4 +4 = 8 , then we look at 7 .... you see , there is no way you can break up 7 from a lower number value . so im going to keep 7 as it is cause f you noticed....8 is split equally with 4 , but when you look at 7 , there is no way at all that you can equally split 7 so im going to solve this problem , how we have it is

4 + 4 = 8 * 7 = 56

makes sense cause you add 2 4's cause 4 + 4 = 8 the n u times 7 with the answer of 4 + 4 and you got your answer

Break method ...

8 - 4 = 4

7 = ? < no equal splitting

4 + 4 = 8 * 7 = 56

hoped this helped

What proportion of the first 10,000 natural numbers contain a 3

Answers

we know that

It is much easier to compute the number of numbers that do not contain a 3.

In the first 10 numbers 9 do not contain a 3.

In the first 100 numbers 81 do not contain a 3. (This is because these numbers are formed by selecting a digit out of

[0, 1, 2, 4, 5, 6, 7, 8, 9] for the first position and another digit out of the same set for the last position and this may be done in

9*9 = 81 ways.

In the first 1000 numbers, reasoning as above, there are

9^(3) numbers that do not contain a 3.

Now the pattern should be becoming obvious.

In the first 10^(n) numbers there are 9^(n) numbers that do not contain a 3.

So

In the first 10^(4) numbers there are 9^(4) numbers that do not contain a 3.

9^(4)= 6,561

10,000- 6,561= 3,439

Thus

the ratio of those numbers that do contain a 3 over the total is equal to

Ratio=(3,439)/(10,000) \n \n Ratio=0.3439

therefore

the answer is

0.3439

In the first 10 -> 10 - 9 = 1 (contain a 3).
In the first 100 -> 100 - 9 * 9 = 19 (contain a 3).
In the first 10^n -> 10^n - 9^n  (contain a 3).


So for 10^4 -> 10^4 - 9^4 = 10.000 - 6.561 = 3.439

The answer is 3.439 numbers contain a 3 in the first 10.000

Can you answer this for me pls i need it ASAP​

Answers

Answer:

24m^3-160m^2+225m+30

Step-by-step explanation:

Ok so i attached it as a picture.