MATHEMATICS HIGH SCHOOL

HELP PLEASE, I don’t understand:(!
HELP PLEASE, I don’t understand:(! - 1

Answers

Answer 1
Answer: Does that say find M/_T. ( /_ is my way of making the angle symbol
Answer 2
Answer:

Answer:m<t =16

Step-by-step explanation:

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Plz factor
2x^2+17x-21

Answers

2x^2 + 17x -21 cannot be factored nicely, if it was +21 you could, but the zeros for this have to gotten using the quadratic equation

-b +/- (b^2-4ac)^1/2
     2a
so

-17 +/- (17^2-4(2)(-21))^1/2
       2(2)
-17 +/- (457)^1/2
       4

so the zeros are roughly 1.094 and -9.594

Reduce 7y + 2y 2 - 7 by 3 - 4y?

Answers

(7y+2y2−7)−(3−4y)

=7y+4y+2y2−7−3

=11y−2y2−10

Hope this helps

Sally works for Mailworks stuffing envelopes. She is paid $0.20 for each mailing she completes. How much does she earn for a week in which she stuffs 523 envelopes?

Answers

If you would like to know how much does Sally earn for a week in which she stuffs 523 envelopes, you can calculate this using the following steps:

$0.20 * 523 envelopes = 0.20 * 523 = $104.6

The correct result would be $104.6.

Solve for x pleasssee help

Answers

Answer:

x=8

Step-by-step explanation:

13=x+5

8=x

Answer:

x = 8

Step-by-step explanation:

Okay, so the top and bottom of a parallelogram are equal (or else it would be a trapezoid), so we just have to construct our cute lil algebraic expression:

x + 5 = 13

So now we have to do the inverse operations thingy:

13 - 5 = 8

So x = 8

tell me if this is wrong so I can fix it

hope this helps:)

Write the function in vertex form
y=-x^2-2x+7

Answers

i hope this helps you

5 students participated in a push-up competition.The amount of push-ups each student completed is listed: 12, 7, 10, 11,5
What was the mean number of push-ups?

Answers

Answer: 9

Step-by-step explanation:

Formula : Mean = \frac{\text{Sum of observations}}{\text{Number of observaions}}

Given: 5 students participated in a push-up competition.

The amount of push-ups each student completed is listed: 12, 7, 10, 11,5.

Mean = (12+7+10+77+5)/(5)

=(45)/(5)=9

Hence, the mean number of push-ups = 9
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If anyone know this , please help thanks
An airliner carries 200 200 passengers and has doors with a height of 70 70 in. Heights of men are normally distributed with a mean of 69.0 69.0 in and a standard deviation of 2.8 2.8 in. Complete parts​ (a) through​ (d). a. If a male passenger is randomly​ selected, find the probability that he can fit through the doorway without bending. The probability is . 6395 . ​(Round to four decimal places as​ needed.)b. If half of the 200 200 passengers are​ men, find the probability that the mean height of the 100 100 men is less than 70 70 in. The probability is nothing . ​(Round to four decimal places as​ needed.) c. When considering the comfort and safety of​ passengers, which result is more​ relevant: the probability from part​ (a) or the probability from part​ (b)? Why? A. The probability from part​ (a) is more relevant because it shows the proportion of flights where the mean height of the male passengers will be less than the door height. B. The probability from part​ (b) is more relevant because it shows the proportion of flights where the mean height of the male passengers will be less than the door height. C. The probability from part​ (a) is more relevant because it shows the proportion of male passengers that will not need to bend. D. The probability from part​ (b) is more relevant because it shows the proportion of male passengers that will not need to bend. d. When considering the comfort and safety of​ passengers, why are women ignored in this​ case? A. There is no adequate reason to ignore women. A separate statistical analysis should be carried out for the case of women. B. Since men are generally taller than​ women, a design that accommodates a suitable proportion of men will necessarily accommodate a greater proportion of women. C. Since men are generally taller than​ women, it is more difficult for them to bend when entering the aircraft.​ Therefore, it is more important that men not have to bend than it is important that women not have to bend.