Which value, when placed in the box, would result in a system of equations with infinitely many solutions?y = 2x – 5

2y – 4x =

Answers

Answer 1

Answer: For a system of equations to have infinitely many solutions it must describe identical lines.
If you multiply the first equation by 2, then move the x term to the left side, you would get 2y-4x=-10
Final Answer:
-10
Hope I helped :)

Answer 2

Answer:

Answer:

-10

Step-by-step explanation:

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Simplify and solve this equation for q: 3q + 5 + 2q – 5 = 65. A. q = 23B. q = 13C. q = 15D. q = 11

Round to the nearest hundredth. 7.546
A. 7.546
B. 7.55
C. 7
D. 7.5

Answers

7.55 would be correct because if there is a 5 or greater it goes up a number if it is a 4 or lower it stays the same

B. 7.55

7.546⇒the underlined is the hundredths place
When rounding it to nearest hundredth, you will look at the digit next to it at the right.
7.546⇒six is greater than 5 so the hundredths place would round up to the next digit which is 5.
$7.546-7.55$

The lengths of two sides of a triangle are 12 inches and 4 inches. Which of the following dimensions is the third side of this triangle?9 inches
8 inches
7 inches
6 inches

Answers

According to the rule that any 2 shorter sides have to be longer (not equal) to the other side, the answer is 9 inches.

4 + x > 12
x > 8

The answer is 9 inches, as x>8 doesn't include 8 in its domain.

Suppose functions are defined as follows.u(x)=x^2+7
w(x)=radical x+4

Find: (w o u)(5)
(u o w)(5)

Answers

The equation to find the ground speed of an airplane is
Vg = Va + Vw where Vg is the ground velocity, Va is the velocity through the air, and Vw is the velocity of the wind.
So, first we find the ground speed of each. This is done by dividing the number of miles by the number of hours.
2370 ÷ 3 = 790 miles per hour
7630 ÷ 7 = 1090 miles per hour
Next, we set them both equal to the equation, making sure that the wind velocity of the first equation is subtracted, because the plane is flying against the wind.
790 = Va - Vw
1090 = Va + Vw
Finally, we have to find the speed of both the wind and the jet. We know that it has to be higher than 790, but lower than 1090. So, logically, it would make sense to find the speed that is perfectly in the middle of the two, because adding or subtracting the same number would equal either speed.
To find this, we do a little subtraction, division, and then addition and subtraction.
1090 - 790 = 300
This means there's a 300 mph difference between the two speeds.
300 ÷ 2 = 150
Half of 300 is 150, so it would make sense that the wind speed is 150 mph, either added or subtracted to the final speed.
790 + 150 = 940
1090 - 150 = 940
Because the two match, that means we've found the speed of both the jet plane, and the wind.
The rate (speed) of the jet is 940 miles per hour (mph), and
The rate of the wind is 150 mph.

u(x) = x² + 7
w(x) = √(x + 4)

(w · u)(5) = (√(5 + 4))((5)² + 7)
(w · u)(5) = (√(9))(25 + 7)
(w · u)(5) = (3)(32)
(w · u)(5) = 96

(u · w)(5) = ((5)² + 7)(√(5 + 4))
(u · w)(5) = (25 + 7)(√(9))
(u · w)(5) = (32)(3)
(u · w)(5) = 96

What is the mean of the data set? {21, 23, 25, 25, 26, 28, 28, 28, 31, 33}

Answers

Answer:

Mean = 26.8

Step-by-step explanation:

In order to calculate the mean of a data set, we add up all the values in the data set and divide the sum by the number of values.

The formula for the mean is:

$\sf Mean = \frac{\textsf{Sum of all values}}{\textsf{Number of values}}$

In this case, the data set is:

{21, 23, 25, 25, 26, 28, 28, 28, 31, 33}

The sum of all the values in the data set is:

21 + 23 + 25 + 25 + 26 + 28 + 28 + 28 + 31 + 33 = 268.

The number of values in the data set is 10.

Substitute the given value in the above formula:

$\sf Mean = ( 268 )/( 10)\n\n = 26.8$

Therefore, the mean of the data set is 26.8.

Answer: 26.8

Step-by-step explanation:

First, we add all the numbers together.

21 + 23 + 25 + 25 + 26 + 28 + 28 + 28 + 31 + 33 = 268

Now, we divide the sum by the amount of numbers we added. Since we added 10 numbers, we divide 268 by 10.

268/10 = 26.8

2. There are 3 apples and 5 oranges in a bag. Determine the probability of selecting anorange, then an apple when they are chosen at random without replacement.