MATHEMATICS MIDDLE SCHOOL

By what percent will a fraction change if its numerator is decreased by 50% and its denominator is decreased by 25%?(It's not 33%, 1/3%, or -33% btw)

Answers

Answer 1

Answer:

Answer:

The fractional change is $(1)/(3)$ % .

Step-by-step explanation:

Given as :

The original fraction = $(x)/(y)$

Where numerator = x

Denominator = y

According to question

The numerator decreased by 50%

Let The new numerator = x' = x - 50% of x

I,e x' = x ( 1 - $(50)/(100)$ )

Or, x' = x ( $(100-50)/(100)$ )

Or, x' = $(50)/(100)$ x

or, x' = $(x)/(2)$ .........A

Again

The new denominator = y' = y - 25% of y

i.e y' = y (1 - $(25)/(100)$ )

Or, y' = y ( $(100-25)/(100)$ )

Or, y' = y ( $(75)/(100)$ )

Or, y' = $(3 y)/(4)$ ............B

So, The new fraction = $(x')/(y')$ = $((x)/(2))/((3 y)/(4))$

Or, $(x')/(y')$ = $(2 x)/(3 y)$

So, The fractional change = $(1-(2)/(3) )/(1)$ × 100

Or, The fractional change = $(1)/(3)$ × 100

Hence, The fractional change is $(1)/(3)$ % . Answer

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3/4g = 5/8 what is t

Answers

3/4g = 5/8

Divide

3/4g/3/4 = 5/8 divided by 3/4

5/8 * 4/3 = 20/24

20/24 = 5/6

Answer: g = 5/6

I think you meant $3/4t = 5/8$ you do it like this:
$3/4t = 5/8$
$4/3$ multiplied by $3/4t = 5/8$ multiplied by $4/3$
Now you multiply the fractions and you should get
$t = 20/24$
But you can simplify it so your final answer should be

Answer: $t = 5/6$

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