the standard equation for a circle is: (x-a)^2 + (y-b)^2 = m^2
x-a)^2 + (y-b)^2 = m^2
means(x-a)(x-a) + (y-b)(y-b) = m^2 then you foil
x^2 - 2ax + a^2 + y^2 - 2by + b^2 = m^2
The greatest common polynomial of 8r³-6r² is 2r². The expression when factored using the greatest common polynomial becomes 2r²(4r-3).
To find the greatest common polynomial of the expression 8r³-6r², we must look for the greatest common factor or polynomial. In this case, we observe that both terms, 8r³ and 6r², have a common factor of 2r².
To factorize the expression, we simply divide each term by the greatest common factor we identified. The factored expression is 2r²(4r-3).
So, the greatest common polynomial in the given expression is 2r².
Learn more about Greatest Common Polynomial here:
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Answer:
I will solve this problem by factor theorem.
If , (x+1) is a factor of the polynomial , then ,if we substitute,x= -1 in f(x), then, f(-1)=0.
Now,
As, f(-1)≠ 0
Option B: (x+1) is not a factor of the polynomial , .
1/2
(x + 12) = 4x – 1
Answer:
One solution, option B for edge2020
Step-by-step explanation:
Answer:
Step-by-step explanation:
4 because as shown below. An equilateral triangle has 3 lines of symmetry.
Answer:
D
Step-by-step explanation:
The zeros are the values of x on the x- axis where the graph crosses.
The graph crosses the x- axis at x = - 4 and x = - 6
Then x = - 4 and x = - 6 are the 2 zeros → D