MATHEMATICS MIDDLE SCHOOL

The sector shows the area of a lawn that will be watered by a sprinkler. What is the area, rounded to the nearest tenth? Use 3.14 for
The sector shows the area of a lawn that will - 1

Answers

Answer 1
Answer:

The area of the sector which representsthe lawn irrigated by the sprinkler is: \mathbf{ 95.5 $ ft^2}

Recall:

  • Area of sector = (\theta)/(360) * \pi r^2
  • Length of arc = (\theta)/(360) * 2 \pi r

Given:

\theta = 30^(\circ)

length of arc = 10 feet

First, find the radius using the length of arc formula.

(\theta)/(360) * 2 \pi r

  • Substitute

10 = (30)/(360) * 2 * 3.14 * r\n\n10 = 0.52r\n\nr = (10)/(0.52) \n\nr = 19.2

radius = 19.2 ft

Find the area of the sector:

Area of sector = (\theta)/(360) * \pi r^2

  • Substitute

= (30)/(360) * * 3.14 * 19.2^2\n\n\mathbf{= 95.5 $ ft^2}

The area of the sector which representsthe lawn irrigated by the sprinkler is: \mathbf{ 95.5 $ ft^2}

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Answer 2
Answer:

Answer:

95.5\ ft^2

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

A circumference of the circle subtends a central angle of 360 degrees

so

using proportion

(2\pi r )/(360^o)=(10)/(30^o) \n\nr=(360(10))/(2(3.14)(30))\n\nr= 19.1\ ft

step 2

Find the area of sector

we know that

The area of the circle subtends a central angle of 360 degrees

so using proportion

Let

x ----> the area of the sector

(\pi r^(2))/(360^o)=(x)/(30^o)\n\nx=(3.14(19.1^2)(30))/(360)\n\nx=95.5\ ft^2

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Answer:

Unit rate defined as the rates are expressed as a quantity 1 such as 2 miles per hour or 5 meter per second.

As per the statement:

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Answer:

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