What is the entropy change of 450 g of water when it changes from liquid to steam at its usual boiling point? For water, 
= 0.334 MJ/kg, 
= 2.26 MJ/kg.
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Answer:
2726.54 J/K
Explanation:
Entropy change =
where
m = mass of water = 450g = 0.45kg
= 2.26 MJ/kg = 2260000 J/kg
T = temperature at which water change from liquid to steam = 100 degree Celsius = 272 + 100 = 373 degree kelvin.
Entropy change = = 2726.54 J/K
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Water is placed at room temperature at 20 degree C
now after some water evaporate at room temperature
so here we can say speed of water molecules will not change as the temperature is same after evaporation
as we know that total kinetic energy is given by
since temperature is same then energy will not change here
now as water evaporate to vapors then we can say that here all molecules are separated more in vapor phase so force of interaction will be less in this phase
And since potential energy depends on the force so potential energy will decrease in this phase
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The given system is a constant pressure systemwhere the work done is the product of the pressure and the volume change.
- The volume to which the gas expands to is approximately 11 liters
Reasons:
Given parameters;
The original volume, V₁ = 40 cm³
The energy released, E = 950 J
Constant pressure applied, P = 650 torr.
Condition: All energy is converted to work to push back the piston
Required:
The volume to which the gas will expand
Solution;
The work done, W = Energy releases, E = 950 J
Work done at constant pressure, W = P·(V₂ - V₁)
Where;
V₂ - The volume to which the gas will expand
Converting the volume to from cm³ to m³ gives;
V₁ = 40 cm³ = 0.00004 m³
Converting the pressure given in torr to Pascals gives;
650 torr. = 86659.54 Pa.
Therefore, we get;
950 J = 86659.54 Pa. × (V₂ - 0.00004 m³)
Converting to liters gives;
- The volume to which the gas expands, V₂ ≈ 11 liters.
Learn more here:
Answer:
The volume needed to expand the gas is = 11 Lit = 11000 
Explanation:
Given :
Initial volume Lit.
Energy J = 9.38 Lit × atm. ⇒ ( 1 Lit×atm. = 101.325 J )
Pressure 650 torr = 0.855 atm. ⇒ ( 1 torr = 0.00132 atm )
In this example we have to be aware of unit conversion system.
From the laws of thermodynamics,
Here in this example, all the energy of combustion is converted into work to push back the piston
Lit =
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We know that,
kilometre = 1000 metre
1000 can be written as 10³ which is kilo.
Given,
88.0km = 88.0×1000
= 88.0×10³m